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kotykmax [81]
3 years ago
9

I'm begging you please help me!!! Thank you! ♡

Mathematics
1 answer:
LiRa [457]3 years ago
5 0
According to the person on top it’s D good lucka,
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Which statements are true about x? Check all that apply. x ∈ B ⋃ C x ∈ B ∩ C x ∈ A ⋃ C x ∈ A ∩ C x ∈ A x ∈ B x ∈ C
nevsk [136]
<h3>Answer:</h3>
  • x ∈ B ⋃ C
  • x ∈ B ∩ C
  • x ∈ A ⋃ C
  • x ∈ B
  • x ∈ C
<h3>Explanation:</h3>

x is in the overlap between B and C, so is an element of either and both B and C.

Because x is an element of C, it is also an element of A∪C, since that union includes all elements of A along with all elements of C (including x).

6 0
4 years ago
Read 2 more answers
Translate the product of a counting number and the next highest counting number into an open sentence.
steposvetlana [31]
So lets say you have a number, x

to get to the next counting number, you add one so
x+1 is the next counting number

product means the result of multiplying os

(x)(x+1)=
distribute [a(b+c)=(ab)+(ac)]
(x^2)+(1x)=x^2+x
4 0
3 years ago
due 7:59 am est. Faith is saving up to buy a new bicycle. She already has $40 and can save an additional $6 per week using money
expeople1 [14]

Answer:

After 8 weeks, Faith would have $88. money saved = 40+6w

7 0
3 years ago
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what will be the total paid on an amortized loan of $15,000 for 5 years at 2 3/4% compounded monthly?
Alex73 [517]

the loan is being amortized, so that doesn't matter for its future value, the simple case that the borrower is paying it in bits monthly.

so, we're really just looking for the future value of the Principal $15000, let's convert theat mixed fraction to improper fraction, and then to a percent format firstly.


\bf \stackrel{mixed}{2\frac{3}{4}}\implies \cfrac{2\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{11}{4}}\implies \stackrel{decimal}{2.75} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt}


\bf \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$15000\\ r=rate\to 2.75\%\to \frac{2.75}{100}\dotfill &0.0275\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &5 \end{cases} \\\\\\ A=15000\left(1+\frac{0.0275}{12}\right)^{12\cdot 5}\implies A=15000\left( \frac{4811}{4800} \right)^{60}\implies A\approx 17208.318305


how did we get 4811/4800?   well, is really just the 1+(0.0275/12), which gives us about 1.0022917 but is a repeating decimal, so 4811/4800 is just the fraction version of it.

5 0
3 years ago
Graph the system of equations on your graph paper to answer the question. {y=−x+3
makkiz [27]
The answer is (x, y) = (-1, 4) hope this helped

5 0
3 years ago
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