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3 years ago

13

Graph the system of equations on your graph paper to answer the question. {y=−x+3

1 answer:

makkiz [27]3 years ago

5 0

The answer is (x, y) = (-1, 4) hope this helped

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How would you solve a inequality like: 15-13(2x+6)< 15-3(6x-7)

Arturiano [62]

<span>15 - 13(2x + 6) < 15 - 3(6x - 7)
15 - 26x - 78 < 15 - 18x + 21
-26x -63 < -18x + 36
-8x < 99
x > -99/8
or
x > - 12.375

</span>

3 0

3 years ago

Read 2 more answers

Given the trinomial x^2+bx+c where both the first and second signs are positive, the signs of the factors will be: A. both negat

Lunna [17]

The answer here is C. The sign of the factors are both positive. We can use the FOIL method as reference in determining the sign of the factors. The 3rd term C is positive; therefore our only option is either both negative or both positive. Looking the middle term, which is positive, we know that the middle term is the sum of the outer and inner in FOIL method, which means, signs of the factors must be both positive

7 0

3 years ago

Find the product of<br> (x2 + 3x + 1)(x2 + x + 2)

Bogdan [553]

Answer: $x^4+4x^3+6x^2+7x+2$

Step-by-step explanation:

To solve the exercise you must apply the following proccedure:

- Apply the distributive property.

- Keep on mind that when you multiply two powers with equal base, you must add the exponents.

- Add like terms.

Therefore, you obtain the following product:

$=x^{(2+2)}+x^{(2+1)}+2x^2+3x^{(1+2)}+3x^{(1+1)}}+6x+x^{2}+x+2\\=x^4+x^3+2x^2+3x^3+3x^2+6x+x^2+x+2\\=x^4+4x^3+6x^2+7x+2$

4 0

3 years ago

Read 2 more answers

Consider function f.

tekilochka [14]

Given:

The function is:

$f(x)=\sqrt{7x-21}$

To find:

The steps of finding the inverse function $f^{-1}(x)$ .

Solution:

We have,

$f(x)=\sqrt{7x-21}$

The steps of finding the inverse function are:

Step 1: Substitute $f(x)=y$ .

$y=\sqrt{7x-21}$

Step 2: Interchange x and y.

$x=\sqrt{7y-21}$

Step 3: Taking square on both sides, we get

$x^2=7y-21$

Step 4: Adding 21 on both sides, we get

$x^2+21=7y$

Step 5: Divide both sides by 7.

$\dfrac{1}{7}x^2+3=y$

Step 6: Substitute $y=f^{-1}(x)$ .

$\dfrac{1}{7}x^2+3=f^{-1}(x)$ , where $x\geq 0$ .

Therefore, the inverse of the given function is $f^{-1}(x)=\dfrac{1}{7}x^2+3$ and the arrangement of steps is shown above.

7 0

3 years ago

What is the inverse of g? <br> g(x) = 3/x+7

ikadub [295]

Given function :-

$\bf \implies g(x) = \dfrac{3}{x}+7$

To find its reverse , substitute y = g(x) .

$\bf \implies y = \dfrac{3}{x}+7$

Interchange x and y .

$\bf \implies x = \dfrac{3}{y}+7$

Solve for y .

$\bf\implies \dfrac{3}{y}= x -7 \\\\\bf\implies y =\dfrac{3}{x-7}$

Replace y with f-¹(x) .

$\implies\boxed{\red{\bf f^{-1}(x) = \dfrac{3}{x-7} }}$

6 0

2 years ago