Answer:
Angle of elevation of the airplane = 17.46 degrees
Step-by-step explanation:
From the picture attached,
An airplane is flying at an altitude of 1500 ft at point A.
Runway starts from point B from which distance of the airplane is 5000 ft.
Now we apply sine rule in the given triangle ABC to measure the angle θ.
sinθ =
sinθ =
=
degrees
Answer:
the answer is 2
Step-by-step explanation:
2+4=6
6+(-4)=6-4=2
Answer:
x = 9.6
Step-by-step explanation:
sin Q = 16/20 Q = 53.13° from the big triangle
16/20 = x/12
192 = 20x
x = 9.6