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Andru [333]
3 years ago
12

How do you solve this problem?

Mathematics
1 answer:
finlep [7]3 years ago
8 0
Can you please take a photo again?
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Can someone plz help 16x - 26c / x = ?
Lerok [7]

Answer:

-10c

Step-by-step explanation:

16x

-26c/x

-----------

-10c

6 0
4 years ago
Find the standard deviation of the following set of data (1.2, 2.3, 5.2, 6.6, 4.8)
Vesna [10]

Answer:

<u>The correct answer s B. 2.21</u>

Step-by-step explanation:

There are three steps to calculate the standard deviation of the set of data given.

n = 5 (5 numbers in the set)

1. Calculate the mean, this way:

(1.2 + 2.3 + 5.2 + 6.6 + 4.8)/5 = 20.1/5 = 4.02

μ = 4.02

2. Calculate the variance, this way:

Sum of the squared difference between each number of the set and the mean divided by the number of elements of the sample minus one.

[(1.2 - 4.02)² + (2.3 - 4.02)² + (5.2 - 4.02)² + (6.6 - 4.02)² + (4.8 - 4.02)²]/4 =

19.568/4 = 4.892

σ² = 4.892

3. Finally, the standard deviation. this way:

Standard deviation is the square root of the variance.

σ² = 4.892

√σ² = √4.892

σ = 2.21

<u>The correct answer s B. 2.21</u>

8 0
3 years ago
a rectangle is constructed with its base on the x-axis and two of its vertices on the parabola y=121-x^2. what are the dimension
insens350 [35]

Answer:

the length is \dfrac{22}{\sqrt{3}} and the width is 121-\left(\dfrac{11}{\sqrt{3}}\right)^2=121-\dfrac{121}{3}=\dfrac{242}{3}.

Step-by-step explanation:

Let points A and B be placed on the x-axis. Their coordinates are A(x_0,0)\ (x_0>0) and B(-x_0,0) (because of parabola symmetry). Two other vertices lie on the parabola, then C(-x_0,121-x_0^2) and D(x_0,121-x_0^2). The length of the side AB is 2x_0 and the length of the side AD is 121-x_0^2. Thus, the area of the rectangle ABCD is

A=2x_0\cdot (121-x_0^2)=242x_0-2x_0^3.

Find the derivative A':

A'=242-2\cdot 3x_0^2=242-6x_0^2.

Equate A' to 0:

242-6x_0^2=0,\\ \\x_0^2=\dfrac{121}{3},\\ \\x_0=\dfrac{11}{\sqrt{3}}.

The maximum area of the rectangle is

A_{max}=242\cdot \dfrac{11}{\sqrt{3}}-2\cdot \left(\dfrac{11}{\sqrt{3}}\right)^3=\dfrac{2662}{\sqrt{3}}-\dfrac{2662}{3\sqrt{3}}=\dfrac{5324}{3\sqrt{3}}\ un^2.

The dimensions of the rectangle are:

the length is \dfrac{22}{\sqrt{3}}\ un. and the width is 121-\left(\dfrac{11}{\sqrt{3}}\right)^2=121-\dfrac{121}{3}=\dfrac{242}{3}\ un.

6 0
4 years ago
Read 2 more answers
What are the values of A1 and R of the geometric series 1 + 3 + 9 + 27 + 81
KATRIN_1 [288]
A1 is the first term, in this case, A1 is 1
R is the ratio between adjacent numbers, in this case, R=3 because 3/1=3, 9/3=3, 27/9=3, 81/27=3
8 0
4 years ago
Read 2 more answers
(Grad point )What is m
GrogVix [38]

Answer:

Either b or c

Step-by-step explanation:

5 0
3 years ago
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