(2 − 3)(1 − ) − (3 − )(3 + )

Mathematics

1 answer:

Lostsunrise [7]2 years ago

4 0

Answer:

your equation is wrong!! the answer is $10$

Step-by-step explanation:

the correct order of the equation is:

$(2-3)(-1)-(-3)(3)$

first, solve in the parentheses from left to right:

$(2-3)(-1)-(-3)(3)=\\(-1)(-1)-(-3)(3)=\\1-(-3)(3)=\\$

If we have 2 negative signs then we will change them to positive :

$1-(-3)(3)=\\1+3(3)\\$

now we have an equation with parentheses, we will multiply $3(3)\\$ because the parentheses go first.

$1+3(3)=\\1+9=10$

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Solve for p... -5(p + 3/5) = -4

Alla [95]

Step-by-step explanation:

-5(p + 3/5 ) = -4

-5p - 3/5 *5 = -4

-5p - 3 = - 4

-5p = -4 +3

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3 years ago

The following data gives the speeds (in mph), as measured by radar, of 10 cars traveling north on I-15. 76 72 80 68 76 74 71 78

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Answer:

71.123 mph ≤ μ ≤ 77.277 mph

Step-by-step explanation:

Taking into account that the speed of all cars traveling on this highway have a normal distribution and we can only know the mean and the standard deviation of the sample, the confidence interval for the mean is calculated as:

$m-t_{a/2,n-1}\frac{s}{\sqrt{n} }$ ≤ μ ≤ $m+t_{a/2,n-1}\frac{s}{\sqrt{n} }$

Where m is the mean of the sample, s is the standard deviation of the sample, n is the size of the sample, μ is the mean speed of all cars, and $t_{a/2,n-1}$ is the number for t-student distribution where a/2 is the amount of area in one tail and n-1 are the degrees of freedom.

the mean and the standard deviation of the sample are equal to 74.2 and 5.3083 respectively, the size of the sample is 10, the distribution t- student has 9 degrees of freedom and the value of a is 10%.

So, if we replace m by 74.2, s by 5.3083, n by 10 and $t_{0.05,9}$ by 1.8331, we get that the 90% confidence interval for the mean speed is: