Answer:
7.8535891e+84
Step-by-step explanation:
Multiply,
40 x 39 x 38 x 37 x 36 x 35 x 34 x 33 x 32 x 31 x 30 x 29 x 28 x 27 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 19 x 18 x 17 x 16 x 15 x 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1/10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 x 30 x 29 x 28 x 27 x 26 x 25 x 24 x 23 x 22 x 21 x 20 x 19 x 18 x 17 x 16 x 15 x 14 x 13 x 12 x 11 x 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = A lot of numbers.
The answer to this question is the last option: “The distance traveled in York Canal is 1/2 the distance traveled on Stover Lake” as 5 is 1/2 of 10
Answer:
It's 70.4 because i subtracted the 2 numbers and it gave me 9.6 just like 80-9.6. I don't know if i'm right, please correct me if i'm wrong. I'm still not sure...
Step-by-step explanation:
43-123= -80
80-9.6=70.4
80-70.4= 9.6
Answer:
.1km
Step-by-step explanation:
The tractor can move .01 km in a second so 10 times .01 is .1
so the tractor can move .1km every 10 seconds
Height of another tree that cast a shadow which is 20ft long is 5 feet approximately
<h3><u>Solution:</u></h3>
Given that tree with a height of 4 ft casts a shadow 15ft long on the ground
Another tree that cast a shadow which is 20ft long
<em><u>To find: height of another tree</u></em>
We can solve this by setting up a ratio comparing the height of the tree to the height of the another tree and shadow of the tree to the shadow of the another tree
![\frac{\text {height of tree}}{\text {length of shadow}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bheight%20of%20tree%7D%7D%7B%5Ctext%20%7Blength%20of%20shadow%7D%7D)
Let us assume,
Height of tree = ![H_t = 4 feet](https://tex.z-dn.net/?f=H_t%20%3D%204%20feet)
Length of shadow of tree = ![L_t = 15 feet](https://tex.z-dn.net/?f=L_t%20%3D%2015%20feet)
Height of another tree = ![H_a](https://tex.z-dn.net/?f=H_a)
Length of shadow of another tree = ![L_a = 20 feet](https://tex.z-dn.net/?f=L_a%20%3D%2020%20feet)
Set up a proportion comparing the height of each object to the length of the shadow,
![\frac{\text {height of tree}}{\text {length of shadow of tree}}=\frac{\text { height of another tree }}{\text { length of shadow of another tree }}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bheight%20of%20tree%7D%7D%7B%5Ctext%20%7Blength%20of%20shadow%20of%20tree%7D%7D%3D%5Cfrac%7B%5Ctext%20%7B%20height%20of%20another%20tree%20%7D%7D%7B%5Ctext%20%7B%20length%20of%20shadow%20of%20another%20tree%20%7D%7D)
![\frac{H_{t}}{L_{t}}=\frac{H_{a}}{L_{a}}](https://tex.z-dn.net/?f=%5Cfrac%7BH_%7Bt%7D%7D%7BL_%7Bt%7D%7D%3D%5Cfrac%7BH_%7Ba%7D%7D%7BL_%7Ba%7D%7D)
Substituting the values we get,
![\frac{4}{15} = \frac{H_a}{20}\\\\H_a = \frac{4}{15} \times 20\\\\H_a = 5.33](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B15%7D%20%3D%20%5Cfrac%7BH_a%7D%7B20%7D%5C%5C%5C%5CH_a%20%3D%20%5Cfrac%7B4%7D%7B15%7D%20%5Ctimes%2020%5C%5C%5C%5CH_a%20%3D%205.33)
So the height of another tree is 5 feet approximately