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Lostsunrise [7]

2 years ago

7

It was estimated that 280 people were going to vote. Goron 35%, Smith 15%, Fishman 40%, Other 10%. If this was true, how many pe

ople would have voted for Goron?

1 answer:

Snowcat [4.5K]2 years ago

7 0

The answer would be 98 people who voted for Goron.

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The sum of three consquetive odd number is 177. Find the numbers.

beks73 [17]

Answer:

57, 59, and 61.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

1<br> Calculate the area of the<br> rectangle.<br> N<br> 11 m <br> 5 1/4 m

antoniya [11.8K]

Answer:

57.75 or 57.8

Step-by-step explanation:

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2 years ago

After hip surgery, your doctor tells you to walk 5 minutes a day. Each day thereafter, you should increase your walk time by 2 m

tatuchka [14]

7 mins a day hope this helps

4 0

3 years ago

Help please my moms going to kill me if I don’t get this right

iragen [17]

Answer:

$x=-\frac{41}{6}$

Step-by-step explanation:

Pay attention to the two tick marks. This indicates that those sides are congruent to each other and so will the angles on the bottom and top. Therefore, we can set up the equation $137+2(-3x+1)=180$ and solve for x:

$137+2(-3x+1)=180$

$137+(-6x+2)=180$

$137-6x+2=180$

$139-6x=180$

$-6x=41$

$x=-\frac{41}{6}$

8 0

2 years ago

Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

$\theta=\frac{2\pi}{3},\frac{4\pi}{3}$

7 0

2 years ago