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In using the multiple regression method, we can model the effects of the different levels of a qualitative independent variable

attashe74 [19]

For the levels of qualitative, the variable called dummy variables is used in the multiple regression method.

According to the statement

we have given that the by which method we use the different levels of a qualitative independent variable and we have to explain about it.

So, For his purpose, we know that the

A dummy variable is a variable that takes values of 0 and 1, where the values indicate the presence or absence of something.

And in the multiple regression method there are a lot of different variables which are used for a qualitative and for this a variable is used which is called the dummy variables.

By this variables we show the analysis between the given data. it gives the output in the 0 and 1 numbers.

So, For the levels of qualitative, the variable called dummy variables is used in the multiple regression method.

Learn more about the Dummy variables here

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3 0

1 year ago

Can anyone help me with this?

matrenka [14]

Answer:

$\sqrt{7}$

Step-by-step explanation:

Given

4 $\sqrt{7}$ - 10 $\sqrt{7}$ + 7 $\sqrt{7}$ ( add the coefficients of the terms )

= (4 - 10 + 7) $\sqrt{7}$

= 1 $\sqrt{7}$

= $\sqrt{7}$

5 0

3 years ago

A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th

OlgaM077 [116]

Answer:

Interval [16.34 , 21.43]

Step-by-step explanation:

First step. <u>Calculate the mean</u>

$\bar X=\frac{(23+18+23+12+13+23)}{6}=18.666$

Second step. <u>Calculate the standard deviation</u>

$\sigma =\sqrt{\frac{(23-18.666)^2+(18-18.666)^2+(23-18.666)^2+(12-18.666)^2+(13-18.666)^2+(23-18.666)^2}{6}}$

$\sigma=\sqrt\frac{18.783+0.443+18.783+44.435+5.666+18.783}{6}$

$\sigma=\sqrt{17.815}=4.22$

As the number of data is less than 30, we must use the t-table to find the interval of confidence.

We have 6 observations, our level of confidence DF is then 6-1=5 and we want our area A to be 80% (0.08).

We must then choose t = 1.476 (see attachment)

Now, we use the formula that gives us the end points of the required interval

$\bar X \pm t\frac{\sigma}{\sqrt n}$

where n is the number of observations.

The extremes of the interval are then, rounded to the nearest hundreth, 16.34 and 21.43

6 0

3 years ago

Does anyone know this?

weeeeeb [17]

Answer:

BC = 10.24

Step-by-step explanation:

You can use the Pythagoras theorem for this question

$a^{2}$ + $b^{2}$ = $c^{2}$

a = 8cm

b = ???

c = 13cm

We will solve for B (length BC)

$a^{2}$ + $b^{2}$ = $c^{2}$

$8^{2}$ + $b^{2}$ = $13^{2}$

Rearrange for b

$b^{2}$ = $13^{2}$ - $8^{2}$

$b^{2}$ = 105

b = $\sqrt{105}$

b = 10.24

7 0

3 years ago

How do you find the equation of line u?

suter [353]

Y=9x+5 theres your answer

7 0

3 years ago