The sides could be 1,14 or 2,7
Since, the system of linear equations are parallel
so, they will never cross or intersect each other
And we know that
solution can only be found if both lines intersect atleast one point
But here , lines are parallel
so, they never intersect each other throughout number line
Since, they never intersect
so, we won't get any common value between both lines
Hence,
There is no solution...........Answer
Answer:
y = 5x2 + 10x - 15
We want this in format y = a(x-h)2 + k
where the vertex will be at (h,k)
y = 5(x2+2x) - 15
Complete the square on x2+2x
y = 5(x2+2x+1) - 15 - 5
We subtract 5 at the end because we are actually adding 5(1) = 5
so we need to remove it also to keep the total equal
y = 5(x+1)2 - 20
The vertex is at (-1,-20)
Answer:
как работать с ю так 87
Step-by-step explanation:
156
Multiply 3x by -6, it gives you -18 so I'm going to say D
