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r-ruslan [8.4K]
3 years ago
13

What fraction of a year is 4 months? ​

Mathematics
1 answer:
MAVERICK [17]3 years ago
6 0

Answer:

One third \frac{1}{3}

Step-by-step explanation:

A year has 12 months, which means that 4 months would be \frac{4}{12}, but since both the numerator and denominator can be divided by 4 this fraction can be simplified to \frac{1}{3}

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Ludmilka [50]
The line is leaning to the left, so the slope is negative, eliminate A and D
when x is 3, y is -2, so C is the correct answer
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3 years ago
A book cover is 8 4/5 inches by 22/25 inches what is the total distance around the perimeter the cover of the book?
ss7ja [257]
2(8 4/5)+2(22/25)
2(44/5)+2(22/25)
2(220/25)+2(22/25)
(440/25)+(44/25)
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4 0
3 years ago
X/2-y+6=0 slope intercept form
Over [174]
X/2-y+6=0
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3 years ago
Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)
zubka84 [21]
\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 


This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

\frac{ \sqrt{-49}}{7-2i-4-9i}

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result: 

\frac{ \sqrt{-49} }{3-11i}

Now, the \sqrt{-49} must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to \sqrt{49}  \sqrt{-1}
This means that we get the result 7i for the numerator.

\frac{7i}{3-11i}

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: x^2 - y^2 =(x+y)(x-y)
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

\frac{7i (3+11i)}{(3-11i)(3+11i)}

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how (3-11i)(3+11i)= 3^2 -(11i)^2 therefore, we can finally write:

\frac{7i(3+11i)}{3^2 - (11i)^2 }

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product 7i(3+11i) = 21i+77i^2.
You should know from your classes that i^2 = -1, thefore the numerator simplifies to -77+21i
You can do it as a curious thing, but simplifying yields the result:
\frac{-77+21i}{130}
7 0
3 years ago
Can i have some help
Katarina [22]

Answer:

I am so sorry but the link will not let me see the question

Step-by-step explanation:

could you put a screen shot of the question and maybe i could try to help :)

3 0
3 years ago
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