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konstantin123 [22]
3 years ago
10

How does the graph of the function g(x) = 2x – 4 differ from the graph of f(x) = 2x

Mathematics
1 answer:
Lena [83]3 years ago
5 0

9514 1404 393

Answer:

  the y-intercepts differ

Step-by-step explanation:

The x-coefficient is the same for each function, so parallel lines are described. The function g(x) has a y-intercept of -4; f(x) has a y-intercept of 0.

The graphs differ in their intercepts.

__

<em>Additional comment</em>

g(x) can be considered to be a translation downward of f(x) by 4 units. The same graph of g(x) can be obtained by translating f(x) to the right by 2 units. That is, both the x-intercepts and y-intercepts differ between the two functions.

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The equation represents an ellipse.
Tom [10]

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B) (-10, -6) and (8, -6)

Step-by-step explanation:

6 0
3 years ago
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A) 20 milligrams of the drug lincomycin is to be given for each kilogram of a person's weight the drug is be mixed with 250 cc o
krok68 [10]

Answer:

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4 0
3 years ago
Please help with this I am completely stuck on it
vaieri [72.5K]

Answer:

f(x)=\sqrt[3]{x-4} , g(x)=6x^{2}\textrm{ or }f(x)=\sqrt[3]{x},g(x)=6x^{2} -4

Step-by-step explanation:

Given:

The function, H(x)=\sqrt[3]{6x^{2}-4}

Solution 1:

Let f(x)=\sqrt[3]{x}

If f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}, then,

\sqrt[3]{g(x)} =\sqrt[3]{6x^{2}-4}\\g(x)=6x^{2}-4

Solution 2:

Let f(x)=\sqrt[3]{x-4}. Then,

f(g(x))=H(x)=\sqrt[3]{6x^{2}-4}\\\sqrt[3]{g(x)-4}=\sqrt[3]{6x^{2}-4} \\g(x)-4=6x^{2}-4\\g(x)=6x^{2}

Similarly, there can be many solutions.

7 0
3 years ago
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Vsevolod [243]

Answer: 1.5 or 1 1/2

Step-by-step explanation:

8 0
3 years ago
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mrs_skeptik [129]

Answer:

A=28

B=18

C=18

D=28

E=28

F=18

G=10

H=5

Step-by-step explanation:

3 0
2 years ago
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