Weird way to write it but alright! (Sideways)
19pq^-2 x 5pq^6 = ?
These problems are pretty much single operations between each of the variables / constants.
So it's like this:
(19*5)(p*p)(q^-2*q^6) = ?
19*5 is 95.
For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2.
p*p is p^2
For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this:
-2 + 6 = 4
(The two is negative, because the power is negative 2)
So, q^4.
Our final answer is all of the combined.... like a so:
95p^2q^4
Answer:
? = h
Step-by-step explanation:
v = lwh
v / wh = lwh / wh
v / wh = l
Hopefully this helped!
Brainliest please?
Answer:
2/8, 3/12, 4/24, 5/20, 6/24, 7/28, 8/32, 9/36, 10/40, etc.
Step-by-step explanation:
Good for Julie! Is there a question that comes with this post?
-TTL
