Answer:
(a) 2 degree celsius per hour
(b) 3 degree celsius per hour.
Step-by-step explanation:
From the question,
(a) Avearge rate of rise in temperature per hour(T') = Rise in temperature(T)/Time required for the rise(t).
T' = T/t.................... Euqation 1
Rise in temperature (T) = 4 degree celsius, t = 10.00 am to noon = 2 hours.
Substitute into equation 1
T' = 4/2
T' = 2 degree celsius per hour.
(b) Also,
Average rate of fall in temperature per hour (T') = Fall in temperature (T)/Time(t)
T' = T/t
Given: T = 6 degree celsius, t = 3:00 pm to 5:00 pm = 2 hours
T' = 6/2
T' = 3 degree celsius per hour
Answer:
The width is 50 yards and the length is 141 yards.
Step-by-step explanation:
Let's call: L the length of the field and W the width of the field.
From the sentence, the perimeter of the rectangular playing field is 382 yards we can formulate the following equation:
2L + 2W = 382
Because the perimeter of a rectangle is the sum of two times the length with two times the width.
Then, from the sentence, the length of the field is 9 yards less than triple the width, we can formulate the following equation:
L = 3W - 9
So, replacing this last equation on the first one and solving for W, we get:
2L + 2W = 382
2(3W - 9) + 2W = 382
6W -18 +2W = 382
8W - 18 = 382
8W = 382 + 18
8W = 400
W = 400/8
W = 50
Replacing W by 50 on the following equation, we get:
L = 3W - 9
L = 3(50) - 9
L = 141
So, the width of the rectangular field is 50 yards and the length is 141 yards.
Answer:
arcPR=125
RQ=125
PR=30
AQ=4
im not done yet and im not sure if im right but hope this helps.
The answer is 13 … just minus 17-4 and it will equal 13
<span>Absolute value of -98 is 98
Hope I helped:D </span>
