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3 years ago

If \triangle ABC△ABC is equilateral, solve for x. x=

Mathematics

2 answers:

Y_Kistochka [10]3 years ago

7 0

Answer:

Lebron james

Step-by-step explanation:

Gwar [14]3 years ago

6 0

Answer:

x = 13

Step-by-step explanation:

The tirangle ABC is given as equilateral. Every angle is therefore =. Not only that, each angle is 60 degrees.

If you need proof of that, remember that x + x + x = 180. Every triangle has 180 degrees.

if 3x = 180 then 1 x is 60

8x - 44 = 60 Add 44 to both sides.

8x = 60 + 44

8x = 104 Divide by 8

x = 104/8

x = 13

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At which points does the graph of f(x)=2x−4 cross the x-axis and y-axis?

blagie [28]

crosses x-axis at (2, 0 ) and y-axis at (0, - 4 )

To find where the graph crosses the x and y axes ( intercepts )

• let x = 0, in the equation for y- intercept

• let y = 0, in the equation for x- intercept

x = 0 : y = 0 - 4 = - 4 ⇒ (0, - 4 )

y = 0 : 2x - 4 = 0 ⇒ 2x = 4 ⇒ x = 2 ⇒ (2, 0 )

6 0

3 years ago

Test the claim that the mean GPA of night students is larger than 3.1 at the .10 significance level. The null and alternative hy

Alborosie

Answer:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

$df = n-1=75-1 =74$

The p value is:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is: 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

Step-by-step explanation:

For this case we want to test the claim that mean GPA of night students is larger than 3.1 at the .10 significance level. The claim needs to be on the alternative hypothesis so then we have the following system of hypothesis:

H 0 : μ = 3.1 H 1 : μ > 3.1

And this test is defined a a right tailed test since the symbol for the alternative hypothesis H1 is >.

We have the following info given:

$\bar X = 3.13 , s =0.03 , n =75$

The statistic to check the hypothesis is given by:

$t = \frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}$

Replacing the info given we got:

$t = \frac{3.13-3.1}{\frac{0.03}{\sqrt{75}}}= 8.66$

The degrees of freedom are given by:

$df = n-1=75-1 =74$

The p value since is a right tailed ted is given by:

$p_v = P(t_{74} >8.66) =3.65x10^{-13}$

The significance level is 0.1 or 10%

And since the p value is very low compared to the significance level we have enough evidence to:

Reject the null hypothesis

6 0

3 years ago

Can someone help me with 13-16 I’ll mark brainliest please guys I’m begging

oee [108]

Answer:

you can look the first 3 up online
16. B

3 0

3 years ago

Read 2 more answers

Solve for n.<br><br> n + 1 = 4(n – 8)<br> i will give a brainliest

yKpoI14uk [10]

n + 1 = 4(n - 8)

n + 1 = 4n - 32

n - 4n = -32 - 1

-3n = -33 / : (-3)

n = 11

6 0

3 years ago

WILL GIVE BRAINLIEST HELP PLEASE

Tamiku [17]

The relation t relates x to y. To determine if it is a function, see if one x value can give two different y values. Since each x value only has one y value, the relation is a function. To check if the inverse is a function, see if any one y value will give multiple x values. By inversing t, there are two values of x for the value of y = -4 (x = 4 and x = 6), so this is NOT a function.

Answer: Relation t is a function. The inverse of relation t is NOT a function.

3 0

3 years ago