Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
Answer:

Step-by-step explanation:
We have been given an equation
. We are asked to solve our given equation.
First of all, we will add 3 to both sides of our equation.


Now, we will divide both sides of our equation by 4.


Upon rounding our answer to nearest thousandth (3 places after decimal) we will get,

Therefore, the solution for our given equation is
.
2x^2+3. the 2x cancel out and the rest is combining like terms
Answer:
4355646
Step-by-step explanation:
45345
Answer:
37
Step-by-step explanation: