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3 years ago

9

Mathematics

1 answer:

hammer [34]3 years ago

8 0

answer: 150 ( 20 / 100 ) = £30

20% can also be written as 20 / 100 as percent means ‘per hundred.’ just multiply that with your number !

alternatively

10% = 150 / 10 = 15

20% = 15 * 2 = £30

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Use the data in the table to find the median mode, and range of the data.

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Answer:

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Mode: 0

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Step-by-step explanation:

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Use Lagrange multipliers to find the maximum and minimum values of f(x,y)=x+4y subject to the constraint x2+y2=9, if such values

Vesnalui [34]

The Lagrangian is

$L(x,y,\lambda)=x+4y+\lambda(x^2+y^2-9)$

with critical points where the partial derivatives vanish.

$L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}$

$L_y=4+2\lambda y=0\implies y=-\dfrac2\lambda$

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Substitute $x,y$ into the last equation and solve for $\lambda$ :

$\left(-\dfrac1{2\lambda}\right)^2+\left(-\dfrac2\lambda\right)^2=9\implies\lambda=\pm\dfrac{\sqrt{17}}6$

Then we get two critical points,

$(x,y)=\left(-\dfrac3{\sqrt{17}},-\dfrac{12}{\sqrt{17}}\right)\text{ and }(x,y)=\left(\dfrac3{\sqrt{17}},\dfrac{12}{\sqrt{17}}\right)$

We get an absolute maximum of $3\sqrt{17}\approx12.369$ at the second point, and an absolute minimum of $-3\sqrt{17}\approx-12.369$ at the first point.

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3 years ago

As a block of ice melts it changes from 1 3/4 lb to 1/4 lb and takes 1/4 hr. What is the rate the ice changes?

Nutka1998 [239]

The rate at which the ice changes is -3/8 lb per hr

<h3>What is the rate the ice changes?</h3>

The given parameters are:

Changes =1 3/4 lb to 1/4 lb

Time = 1/4 hr.

The rate the ice changes is calculated as:

Rate = Change/Time

So, we have

Rate = (1/4 lb - 1 3/4 lb)/(1/4 hr)

Evaluate the difference

Rate = (-1 1/2 lb)/(1/4 hr)

Evaluate the quotient

Rate = -3/8 lb per hr

Hence, the rate at which the ice changes is -3/8 lb per hr