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alexgriva [62]
4 years ago
11

Solve 2a − 5d = 30 for d

Mathematics
2 answers:
vekshin14 years ago
7 0
2a₋5d=30

⇒2a-30 = 5d

⇒d = (2a-30)÷5
valina [46]4 years ago
6 0
2a - 5d = 30\\
5d=2a-30\\
d=\dfrac{2a-30}{5}
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Justin is going to the school dance. He went to the mall and bought three new shirts for $21.99 each and a new pair of dress sho
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C. Multiply and add

Cost = (3×21.99)+45.99
Cost = $111.96
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2x +(3y+8z)=(2x+3y) is an example of which property?
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I think it's Real numbers
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Here is the full question
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There's 10 letters in volleyball. 4 of them are l's. So 4/10.
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Pedro works as a newspaper deliverer. He receives a base pay plus an additional amount per newspaper delivered. Last week, Pedro
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Y=mx+b
x=number of newspapers
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37.5=5m+b

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3 years ago
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Use the Distance Formula and the Pythagorean Theorem to find the distance between each pair of points. M (10, −4) and N (2, −7)
xenn [34]

Answer:

d=\sqrt{73}\approx8.54

Step-by-step explanation:

So we have the two points (10,-4) and (2,-7).

And we want to find the distance between them using the Distance Formula and the Pythagorean Theorem. Let's do each one individually.

1) Distance Formula.

The distance formula is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2

Let's let (10,-4) be (x₁, y₁) and let's let (2,-7) be (x₂, y₂). So:

d=\sqrt{((2)-(10))+((-7)-(-4))^2

Simplify:

d=\sqrt{(2-10)^2+(-7+4)^2

Subtract:

d=\sqrt{(-8)^2+(-3)^2

Square:

d=\sqrt{64+9}

Add:

d=\sqrt{73}

Approximate:

d\approx8.54

So, the distance between (10,-4) and (2,-7) is approximately 8.54 units.

2) Pythagorean Theorem

Please refer to the graph.

So, we want to find the distance. This will be the length of the red line, or the hypotenuse.

First, let's find the length of the two legs.

The longer leg will be the difference between the two x-coordinates. So, the length of the longer leg is:

(10-2)=8

Note: It doesn't matter if we do 2-10, which gives -8, since we are going to square anyways. Also, distance is always positive, so 8 would be our answer.

And the shorter leg is the difference between the two y-coordinates. Namely:

(-7-(-4))=-3=3

So, the shorter leg is 3 units.

So now, we can use the Pythagorean Theorem, which is:

a^2+b^2=c^2

Substitute 8 for a and 3 for b. So:

(8)^2+(3)^2=c^2

Square:

64+9=c^2

Add:

c^2=73

Take the square root:

c=\sqrt{73}\approx8.54

This is the same as our previous answer, so we can confirm that it's correct.

So, using both the distance formula and the Pythagorean Theorem, the distance between the two points is approximately 8.54.

And we're done!

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3 years ago
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