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Mila [183]
3 years ago
13

26287091 rounded to 5 decimal places

Mathematics
1 answer:
timama [110]3 years ago
7 0
<span>rounded to 5 decimal places:  26287091.00000</span>
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Let x = number of students in each of the remaining rows

266 = (10 x 20) + (5 x 8) + 2x
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what’s the difference between the area of the larger circle and the area of the smaller circle? in pi
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Answer:

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361-256= 105

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3 years ago
Monthly sales of an SUV model are expected to increase at the rate of S′1t2 = -24t 1&gt;3 SUVs per month, where t is time in mon
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The company will continue to manufacture this model for 19 months.

The question is ill-formatted. The understandable format is given below.

An SUV model's monthly sales are anticipated to rise at a rate of

S'(t)=-24^{1/3} SUVs each month, where "t" denotes the number of months and "S(t)" denotes the monthly sales of SUVs. When monthly sales of 300 SUVs are reached, the business intends to discontinue producing this model.

Find S if monthly sales of SUVs are 1,200 at time t=0 (t). How long will the business keep making this model?

Given S'(t)=-24^{1/3} ... ... (1)

Condition (1) at t=0; s(t) =1200

We find S(t)=300 then t=?

a) We find S(t)

from S'(t)=-24^{1/3}

\implies \frac{dS(t)}{dt}=-24t^{1/3} ~~[\because X'(t)=\frac{dX}{dt} \\\implies dS(t) = -24t^{1/3}dt\\

On Integrating both sides

S(t)=-18t^{4/3}+c ~...~...~(2)

Now, at t=0 then S(t)=1200

So, from (2)

1200=0+c

⇒c=1200

\thereforefrom eq (2)

S(t)=-18t^{4/3}+1200 ~...~...~(3)

b) Considering that the firm intends to cease production of this model once monthly sales exceed 300 SUVs.

So, take S(t)=300

from eq (2) 300=-18t^{4/3}+1200

t^{4/3}=\frac{1200-300}{18}\\=\frac{900}{18}=50\\\implies t=50^{3/4}\\\implies t=18.8030

Hence the company will continue 18.8020 months.

Learn more about integration here-

brainly.com/question/18125359

#SPJ10

8 0
2 years ago
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