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Alexus [3.1K]
2 years ago
12

How many solutions to this are there??

Mathematics
2 answers:
brilliants [131]2 years ago
7 0

Answer:

there is only one solution and the answer is 0

hope this helps! Stay safe <3

Step-by-step explanation:

Leokris [45]2 years ago
6 0

Answer:

d

Step-by-step explanation:

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A 15 pound bag of candy cost $9.99. How much does 1 pound of candy cost? How do you know? Make sure to show all work and answer
Law Incorporation [45]

All you would do is divide 9.99/15 to get how much one pound costs.

The answer would be around 66 or 67 cents.

9.99/15=.666

5 0
3 years ago
Read 2 more answers
What is u = kx + ух, for x
Ivahew [28]

Answer:

<h2>x=  \frac{u}{k + y}</h2>

Step-by-step explanation:

u = kx + ух

First of all factorize x out at the right side of the equation

That's

u = x(k + y)

Divide both sides by ( k + y) to make x stand alone

That's

<h3>\frac{x(k + y)}{k + y}  =  \frac{u}{k + y}</h3>

We have the final answer as

<h3>x =  \frac{u}{k + y}</h3>

Hope this helps you

6 0
3 years ago
A 5-column table has 4 rows. The first column has entries A, B, C, Total. The second column is labeled X with entries 15, 5, 30,
Ugo [173]

Answer:

A and X

Step-by-step explanation:

Got it right on edge-nuity

8 0
2 years ago
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Leon throws a ball off a cliff. The graph represents a relation that models the ball’s height, h, in feet over time, t, in secon
Svetlanka [38]

Answer:

The answer is A :))

Step-by-step explanation:

4 0
3 years ago
the numbers 1,2,3,4, and 5 are written on slips of paper, and 2 slips are drawn at random one at a time without replacet. find t
Tresset [83]

Consider such events:

A - slip with number 3 is chosen;

B - the sum of numbers is 4.

You have to count Pr(A|B).

Use formula for conditional probability:

Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}.

1. The event A\cap B consists in selecting two slips, first is 3 and second should be 1, because the sum is 4. The number of favorable outcomes is exactly 1 and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event A\cap B is

Pr(A\cap B)=\dfrac{1}{20}.

2. The event B consists in selecting two slips with the sum 4. The number of favorable outcomes is exactly 2 (1st slip 3 and 2nd slip 1 or 1st slip 1 and 2nd slip 3) and the number of all possible outcomes is 5·4=20 (you have 5 ways to select 1st slip and 4 ways to select 2nd slip). Then the probability of event B is

Pr(B)=\dfrac{2}{20}=\dfrac{1}{10}.

3. Then

Pr(A|B)=\dfrac{\frac{1}{20} }{\frac{1}{10} }=\dfrac{1}{2}.

Answer: \dfrac{1}{2}.

5 0
3 years ago
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