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Alexus [3.1K]
2 years ago
12

How many solutions to this are there??

Mathematics
2 answers:
brilliants [131]2 years ago
7 0

Answer:

there is only one solution and the answer is 0

hope this helps! Stay safe <3

Step-by-step explanation:

Leokris [45]2 years ago
6 0

Answer:

d

Step-by-step explanation:

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What is 8blank7 hundred divided by 4 equal
Gnoma [55]
\frac{870}{4} = \frac{435}{2} &#10;

<span>(Decimal: 217.5)
</span>
For if its
\frac{8700}{4}

Then is =2175

~ Hope this helps 
3 0
3 years ago
Please help anyone and explain please
umka2103 [35]

So if you distribute 4 in the first parentheses, you get 12x+20y+8z.

Then you distribute 3 in the second parentheses. You'll get 3x-3z. That all equals 12x+20y+8z+3x-3z.

Now you have to start combining numbers with the same variable. Start with x. 12x+3x is 15x.

y has no other common variable, it's left alone.

8z-3z is 5z

All together now with the numbers in simpler form, the equation is 15x+20y+5z

Jenna's would be the right answer because when you distribute 5 in her answer you get 15x+20y+5z

5 0
3 years ago
Read 2 more answers
Find the Value of 2a2+5b2
Valentin [98]

Answer:

I get 92 but not really sire

3 0
3 years ago
Which of the following could NOT be the lengths of the sides of a triangle?
Furkat [3]

Given:

Sides of triangles in the options.

To find:

Which could NOT be the lengths of the sides of a triangle.

Solution:

Condition for triangle:

Sum of two smaller sides of a triangle must be greater than the longest side.

In option A,

5+5=10>5

Sides 5 in, 5 in, 5 in are the lengths of the sides of a triangle.

In option B,

10+15=25>20

Sides 10 cm, 15 cm, 20 cm are the lengths of the sides of a triangle.

In option C,

3+4=7>5

Sides 3 in, 4 in, 5 in are the lengths of the sides of a triangle.

In option D,

8+5=13

Since, the sum of two smaller sides is less than the longest side, therefore the sides 8 ft, 15 ft, 5 ft are not the lengths of the sides of a triangle.

Therefore, the correct option is D.

8 0
3 years ago
Write an equation of a parabola that opens to the left, has a vertex at the origin, and a focus at (–4, 0).
8_murik_8 [283]

Answer:

y^{2}=-16x

Step-by-step explanation:

we know that

The standard equation of a horizontal parabola is equal to  

(y-k)^{2}=4p(x-h)

where

(h,k) is the vertex

(h+p,k) is the focus

In this problem we have

(h,k)=(0,0) ----> vertex at origin

(h+p,k)=(-4,0)

so

h+p=-4

p=-4

substitute the values

(y-0)^{2}=4(-4)(x-0)

y^{2}=-16x

8 0
3 years ago
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