Answer:
(-9/7,-26/7)
[more detailed at the bottom of the explanation]
Step-by-step explanation:
I am assuming that this is a system of equations...
So, knowing that y is equal to x + 5, you would plug that in the second equation and find x. Then you would plug x and find y.
—————
Step 1)
Equation 1:
y = (x + 5)
Equation 2:
5x + 2y = 1
Equation 2 can also be written as:
5x + 2(x+5) = 1
I wrote x+5 instead of y because the first equation tells us that y is equal to x + 5.
—————
Step 2)
Solve for x .
5x + 2(x+5) = 1
5x + 2x + 10 = 1
7x + 10 = 1
7x = 1 - 10
7x = -9
x = -9/7
—————
Step 3)
Plug the x value back in the first equation.
y = -9/7 + 5
y = -26/7
—————
Solution:
x = -9/7
y = -26/7
In ordered pair form:
(-9/7,-26/7)
————— ————— —————
Hope this helps !!!!!!!
Answer:
36.58% probability that one of the devices fail
Step-by-step explanation:
For each device, there are only two possible outcomes. Either it fails, or it does not fail. The probability of a device failling is independent of other devices. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
In which 
is the number of different combinations of x objects from a set of n elements, given by the following formula.
And p is the probability of X happening.
A total of 15 devices will be used.
This means that 
Assume that each device has a probability of 0.05 of failure during the course of the monitoring period.
This means that 
What is the probability that one of the devices fail?
This is 
36.58% probability that one of the devices fail
But you're already done....
Sorry I’m just commenting to do it
Answer:
Yes, because when the values are substituted in, the equation becomes a true statement
Step-by-step explanation:
plug in the values for x and y and see if the equation makes sense
x=3
y=11
1/3(3)+11=12
1+11=12
12=12
Since the above equation is true, the point is a solution for the linear equation.
