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KengaRu [80]
3 years ago
15

Find the measures of angles 1,2,3

Mathematics
1 answer:
dalvyx [7]3 years ago
5 0

Answer:BUUFJF

Step-by-step explanation:

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A triangular banner has an area 1500 square feet. Find the measures of the base and height of the triangle if the base is five-s
erastova [34]

Answer:

  • base: 50 ft
  • height: 60 ft

Step-by-step explanation:

The formula for the area of a triangle is ...

  A = (1/2)bh

Filling in the numbers you are given, you get ...

  1500 = (1/2)(5/6h)(h)

  3600 = h^2 . . . . . . . . . multiply by 12/5

  60 = h . . . . . . . . . . . . . .square root

  b = 5/6·60 = 50 . . . . . . base is 5/6 of height

The measures of the base and height are 50 ft and 60 ft, respectively.

4 0
3 years ago
Help, answer one that hasn’t been answered
SVEN [57.7K]

4x + 2x = < y

This is because the opposite sides (which is 4x and 2x) of a triangle add up to the exterior angle (<y).

We have to find X.

As you know:

3x + 4x + 2x = 180

because the angles of a triangle add up to 180.

When we add them:

9x = 180

x =  \frac{180}{9}

The 9 is multiplying with the X. We want X only and not 9 with it. So, when we take 9 to the other side, it becomes divide. As a result, the answer to x is:-

x = 20

Substitute value of x into 4x and 2x to find the exterior angle:-

4x:

4(20) = 80

2x:

2(20) = 40

When we add them we get the answer for angle Y:-

80 + 40 = 120

Therefore, we can conclude that:

< y = 120 \: degrees

8 0
3 years ago
4(6 – 5x)+8(4 – 5x)<br> Please help
strojnjashka [21]
The answer is -60x + 56

4(6 - 5x) + 8(4 - 5x)

24 - 20x + 32- 40x

56 - 60x or you can write it as -60x + 56
3 0
3 years ago
PLEASE HELP ASAP! URGENT!
Nonamiya [84]

Answer:

It would be a negative number, no matter what negative integer you put it as.

Step-by-step explanation:

For example, lets substitute -2

f(-2) = -8-4-1 = -13; a negative number

4 0
3 years ago
Give the following equations determine if the lines are parallel perpendicular or neither
GaryK [48]

In order to determine whether the equations are parallel, perpendicular, or neither, let's simply each equation into a slope-intercept form or basically, solve for y.

Let's start with the first equation.

\frac{6x-5y}{2}=x+1

Cross multiply both sides of the equation.

6x-5y=2(x+1)6x-5y=2x+2

Subtract 6x on both sides of the equation.

6x-5y-6x=2x+2-6x-5y=-4x+2

Divide both sides of the equation by -5.

-\frac{5y}{-5}=\frac{-4x}{-5}+\frac{2}{-5}y=\frac{4}{5}x-\frac{2}{5}

Therefore, the slope of the first equation is 4/5.

Let's now simplify the second equation.

-4y-x=4x+5

Add x on both sides of the equation.

-4y-x+x=4x+5+x-4y=5x+5

Divide both sides of the equation by -4.

\frac{-4y}{-4}=\frac{5x}{-4}+\frac{5}{-4}y=-\frac{5}{4}x-\frac{5}{4}

Therefore, the slope of the second equation is -5/4.

Since the slope of each equation is the negative reciprocal of each other, then the graph of the two equations is perpendicular to each other.

5 0
1 year ago
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