Answer:
2,2
-10
that's the answer to both of them
The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.
According to the statement
We have a given that the maximum sum of the positive integers is 400.
And we have to find the value of n which is a maximum number of integers by which the value of sum become 400.
So, to find the value of the n we use the
A.P. Series'Summation formula
According to this,
S = n (n+1)/2
Here the value of s is 401
Then
S = n (n+1)/2
401 = n (n+1)/2
401*2 = n (n+1)
802 =n (n+1)
n (n+1) = 802
n^2 + n -802 =0
By the use of the Discriminant formula the
value of n becomes n = -28 and n = 27.
The negative value of n is neglected.
Therefore the value of n is 27.
So, The maximum number of integers is 27 that can be added together before the summation of the A.P. Series exceeds 401.
Learn more about maximum number of integers here brainly.com/question/24295771
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Answer:C
Step-by-step explanation:
See photo
Step-by-step explanation:
By AAS congruence, triangles RNM and RNP are congruent. Hence 7x = 2x + 25, x = 5.
Line RM = 7x = 7(5) = 35 units.
Use distributive property
6x + 12 = -8x + 2 + 6x
Now simply
6x + 12 = -2x + 2
8x + 12 = 2
8x = -10, x = -10/8. Simplify: x = -5/4
Solution: x = -5/4
