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2 years ago

Help me with this question please!! :)

Mathematics

1 answer:

Leona [35]2 years ago

4 0

Answer: 13/69

Step-by-step explanation:

13 students are female and got a B out of a total of 69 students, so the probability is 13/69

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Please help on this problem

Harlamova29_29 [7]

Answer: EP is 12 and EO is about 10.91.

To find the length of EP, we can use the Pythagorean Theorem with the 2 legs of the right triangle it would form, EC and CP. CP would be 5 because it is the midpoint of the side.

5^2 + (EP)^2 = 13^2
EP = 12

Now, to find EO, we write and solve another Pythagorean Theorem equation using 12 for EP.

5^2 + (EO)^2 = 12^2
EO equals the square root of 119 or about 10.91.

6 0

3 years ago

For the following right triangle, find the side length x. Round your answer to the nearest hundredth.

alukav5142 [94]

Answer:

use a2+b2=c2 so

Step-by-step explanation:

11(squared)+b(squared)=13(squared)

=121+b2=169

-121. -121

b2= 48

square root 48

Side B= 6.928

and then just round 6.928

hope this helped

3 0

3 years ago

I need help ASAP please!!

vagabundo [1.1K]

Answer:

x = 13 , y = 29

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask!

4 0

3 years ago

B/5>-1<br> Solve the inequality. Graph and check the solution.

Usimov [2.4K]

Answer:

b>-5

Step-by-step explanation:

$\frac{b}{5} > - 1$

Multiply by 5 to isolate b.

$b > - 5$

If you graph this on a line, it would be a hollow point facing the right, since it's any number greater than five, not including 5.

If you put any number greater than -5, you'll output greater than - 1.

4 0

3 years ago

Can someone please explain how to solve this step by step with answer? Thank you.

lidiya [134]

well, she put 4000, and she earned in interest 960, so her accumulated amount is just their sum, 4960.

now, it doesn't say, so we're assuming is <u>simple interest</u>, as opposed to compound interest.

$\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&960\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to r\%\to \frac{r}{100}\dotfill\\ t=years\dotfill &3 \end{cases} \\\\\\ 960=(4000)(r)(3)\implies \cfrac{960}{(4000)(3)}=r\implies 0.08=r \\\\\\ \stackrel{\textit{converting to percentage}}{r=0.08\cdot 100}\implies r=\stackrel{\%}{8}$

let's make the rate 1% greater then, and check

$\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to \stackrel{8+1}{9\%}\to \frac{9}{100}\dotfill&0.09\\ t=years\dotfill &3 \end{cases} \\\\\\ I=(4000)(0.09)(3)\implies I=1080 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{at 9\%}}{1080}-\stackrel{\textit{at 8\%}}{960}\implies \stackrel{\textit{that much more}}{120}$

4 0

3 years ago