Answer:
9.
h(x)=-x-1
let y =-x-1
interchanging role of x & y
x=-y-1
y=-x-1
h-¹(x)=-x-1
again
f(x)=(2-3x)/2
let
y=(2-3x)/2
interchanging role of x & y
x=(2-3y)/2
2x-2=-3y
y=(2-2x)/3
f-¹(x)=(2-2x)/3
<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>f</u><u>u</u><u>n</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>a</u><u>r</u><u>e</u><u> </u><u>n</u><u>o</u><u>t</u><u> </u><u>i</u><u>n</u><u>v</u><u>e</u><u>r</u><u>s</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>o</u><u>t</u><u>h</u><u>e</u><u>r</u><u>.</u>
10.
f(x)=-x+3
let y=-x+3
interchanging role of x & y
x=-y+3
y=3-x
f-¹(x)=-x+3
equal to g(x)=-x+3
<u>Given function are</u><u> inverse of each other.</u>
Answer:
3 hours and 21 miinutes
Step-by-step explanation:
Answer:
in confused on what the question is asking is it multiple questions
Answer:
y -11 = 2(x -3)
Step-by-step explanation:
The slope of the given line is the x-coefficient: 2. The parallel line will have the same slope.
When you know the slope and a point on the line, it is convenient to use the point-slope form of the equation of a line:
y -k = m(x -h) . . . . . . line with slope m through point (h, k)
Your line's equation is ...
y -11 = 2(x -3)
Answer:
(-2,17) i think i am not sure
Step-by-step explanation:
