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guapka [62]
2 years ago
8

What are the solutions of the equation y = negative 2 x squared + 9 x minus 4 shown in the graph below? On a coordinate plane, a

parabola opens down and goes through (0, negative 4), has a vertex around (2.5, 7), and goes through (4, 0). a. x = negative one-half, 4 c. x = one-third, 4 b. x = negative 4, 4 d. x = one-half, 4 Please select the best answer from the choices provided A B C D
Mathematics
1 answer:
katovenus [111]2 years ago
5 0

Answer:

c

Step-by-step explanation:

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Check all of the ordered pairs that satisfy the equation below.y=2/5x
zvonat [6]

We are going to do this step by step:

Let's start with option A

A.

X = 25 and Y = 5/2

y=\frac{2}{5}\cdot x=\frac{2}{5}\cdot25=\frac{2\cdot25}{5}=\frac{50}{5}=\frac{5\cdot10}{5\cdot1}=10

In this case, when X = 25 , then Y = 10 ,which is different to 5/2

B.

X = 14 , Y = 35

y=\frac{2}{5}\cdot14=\frac{28}{5}

In case, when X = 14, then Y = 28/5, which is different to 35

C.

X = 40 , Y = 24

y=\frac{2}{5}\cdot40=\frac{80}{5}=16

Similarly, in this case, when X = 40, then Y = 16, which is different to 24

D.

X = 10 , Y=4

y=\frac{2}{5}\cdot10=\frac{20}{5}=4

Now, in this case, we can see that when X = 10, then Y = 4 which is the same as the given value of Y

E.

X = 50 , Y = 20

y=\frac{2}{5}\cdot50=\frac{100}{5}=20

In this case, the values of Y are also the same.

F.

X = 30 , Y = 12

y=\frac{2}{5}\cdot30=\frac{60}{5}=12

Again, in this case, the values of Y are the same, so the pair satisfies the equation.

In conclusion: options D, E and F satisfy the equation

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10 months ago
What is 26 divided by 503?
Hatshy [7]

Answer:0.05168986083

Step-by-step explanation:

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2 years ago
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Find the solution to the system of linear equations y = 5x + 4 and y = −3x + 12 using the intersection method. Check your answer
Umnica [9.8K]

Answer:

The solution to the system of linear equations is (1,9).

Step-by-step explanation:

The given system of linear equations

y=5x+4            ... (1)

y=-3x+12           .... (2)

Subtract equation (2) from equation (1) to eliminate y.

y-y=(5x+4)-(-3x+12)

0=5x+4+3x-12

On combining like terms, we get

0=(5x+3x)+(4-12)

0=8x-8

Add 8 on both sides.

0+8=8x-8+8

8=8x

Divide both sides by 8.

1=x

The value of x is 1.

Substitute x=1 in equation (1).

y=5(1)+4

y=5+4

y=9

The value of y is 9.

Therefore the solution to the system of linear equations is (1,9).

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