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guapka [62]
2 years ago
8

What are the solutions of the equation y = negative 2 x squared + 9 x minus 4 shown in the graph below? On a coordinate plane, a

parabola opens down and goes through (0, negative 4), has a vertex around (2.5, 7), and goes through (4, 0). a. x = negative one-half, 4 c. x = one-third, 4 b. x = negative 4, 4 d. x = one-half, 4 Please select the best answer from the choices provided A B C D
Mathematics
1 answer:
katovenus [111]2 years ago
5 0

Answer:

c

Step-by-step explanation:

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Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

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T(3,-5)\to T'(-6-3,-5)

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