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taurus [48]
3 years ago
9

|3m-3|=9 plz solve with work and two answers

Mathematics
1 answer:
Arisa [49]3 years ago
4 0

Answer:

m=4 , m=-2

Step-by-step explanation:

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Use the function below to find F(-4).<br><br> F(x) = 2^x
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To answer this item, note that what needs to be done is to substitute -4 to all x's in the equation. That is,
                     F(x) = 2^x
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                     F(-4) = 2^(-4) = 1/16 or 0.0625
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Find the distance between the points (4,10) and (0,0) the answer must be a whole number
Rina8888 [55]

Answer:

d = 2\sqrt{29}

Step-by-step explanation:

d= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d= \sqrt{(0-4)^2+(0-10)^2}\\d= \sqrt{(-4)^2+(-10)^2}\\d= \sqrt{16+100}\\d= \sqrt{116}\\d=2 \sqrt{29}

6 0
3 years ago
An airplane is flying from knoxville to new york. The distance it travels in miles, d, is related to the time in seconds, t, by
Zigmanuir [339]

Answer:

0.12 miles is it flying per second.

Step-by-step explanation:

The distance d is related to time t in seconds is given by the equation as follows :

d =0.12 t

We need to find how many miles is it flying per second.

\dfrac{d}{t}=0.12\\\\\dfrac{\text{miles}}{\text{second}}=0.12

So, the speed of the airplane is 0.12 miles per second, Hence, 0.12 miles is it flying per second.

5 0
2 years ago
A bucket that weighs 5 lb and a rope of negligible weight are used to draw water from a well that is 60 ft deep. The bucket is f
mestny [16]

Answer:

The value is W= 2640 \  ft \cdot lb

Step-by-step explanation:

From the question we are told that

The weight of the bucket is F =  5 lb

The depth of the well is x_1 =  60 \ ft

The weight of the water is W_w  =  42 lb

The rate at which the bucket with water is pulled is v  = 1.5 \  ft/s

The rate of the leak is r = 0.15 lb/s

Generally the workdone is mathematically represented as

W =  \int\limits^{x_1}_{x_o} {G(x)} \, dx]

Here G(x) is a function defining the weight of the system (water and bucket ) and it is mathematically represented as

G(x) =  F  +  (W_w- Ix)

Here I is the rate of water loss in lb/ft mathematically represented as

I  = \frac{r}{v}

=> I  = \frac{0.15 }{1.5 }

=> I  = 0.1

So

G(x) =  5  +  (42- 0.1x)

=> G(x) =  47- 0.1x)

So

W =  \int\limits^{60}_{0} {47- 0.1x} \, dx]

=> W =  [47x - \frac{0.1x^2}{2} ]|\left 60} \atop {0}} \right.

=> W= [47(60) - 0.05(60)^2]

=> W= 2640 \  ft \cdot lb

7 0
3 years ago
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