Answeerrrrr asapppooaoaoaoao please need helppppp

Mathematics

2 answers:

AlekseyPX3 years ago

5 0

Answer:

1a. Yes

1b. No

1c. Yes

Step-by-step explanation:

balandron [24]3 years ago

5 0

Answer:

1a. 2/5 x 25 = 50/5 = 10 and 10 = 10 so yes

1b. 5 + 5 = 10 10 does not equal 15 so no

1c. 5 x 5 = 25 and 25 = 25 so yes

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A certain quadrilateral has two pairs of parallel sides. The opposite sides are equal in length. There are also 4 right angles.

DENIUS [597]

Answer:

12 + 12 = 24

Step-by-step explanation:

P = 2L + 2W

P = 2*16 + 2W

P = 56

56 = 32 + 2W Subtract 32 from both sides

56 - 32 = 2W

24 = 2W Divide by 2

24/2 = 2W/2

12 = W

The answer you want is 2 * 12 = 24

6 0

3 years ago

The vertices of triangle RST are R (-7, 5), S(17, 5), T(5, 0). What is the perimeter of triangle RST?

MaRussiya [10]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ R(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad S(\stackrel{x_2}{17}~,~\stackrel{y_2}{5}) ~\hfill RS=\sqrt{(~~ 17- (-7)~~)^2 + (~~ 5- 5~~)^2} \\\\\\ ~\hfill RS=\sqrt{( 24)^2 + ( 0)^2}\implies \boxed{RS=24} \\\\\\ S(\stackrel{x_1}{17}~,~\stackrel{y_1}{5})\qquad T(\stackrel{x_2}{5}~,~\stackrel{y_2}{0}) ~\hfill ST=\sqrt{(~~ 5- 17~~)^2 + (~~ 0- 5~~)^2}$

$~\hfill ST=\sqrt{( -12)^2 + ( -5)^2}\implies \boxed{ST=13} \\\\\\ T(\stackrel{x_1}{5}~,~\stackrel{y_1}{0})\qquad R(\stackrel{x_2}{-7}~,~\stackrel{y_2}{5}) ~\hfill TR=\sqrt{(~~ -7- 5~~)^2 + (~~ 5- 0~~)^2} \\\\\\ ~\hfill TR=\sqrt{( -12)^2 + (5)^2}\implies \boxed{TR=13} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \stackrel{\textit{\LARGE perimeter}}{24~~ + ~~13~~ + ~~13\implies \text{\LARGE 50}}~\hfill$