Answer:
True
KE = 1/2 mv^2
m = 1500 kg
v = 3 m/s
KE = 1/2 (1500 kg)(3 m/s)^2
KE = (750 kg)(9 m^2/s^2)
KE = 6,750 J
Answer:
its n+20-55-35
Step-by-step explanation:
Answer:
15°
Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.