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creativ13 [48]
4 years ago
7

Write a function based on the given parent function and transformations in the given order

Mathematics
1 answer:
kondaur [170]4 years ago
4 0

Answer:

y=-\left(x-2\right)^{2}-4 is the resultant function after transformations.

Step-by-step explanation:

Parent function is given as:

y=x^2 (Graph 1 in attachments, it is a parabola)

Let us apply the transformations step by step:

<u>1. Shift 2 units to the right </u>i.e.

change the value of x by 2.

The equation of a parabola can be: y=(x-a)^2 where a is the point on x axis which is the axis of symmetry.

Right side means the equation becomes:

y=(x-2)^2  (Graph 2 in attachments)

<u>2. Reflect over x axis</u> i.e.

change the sign of y from + to -.

y=-(x-2)^2 (Graph 3 in attachments)

3. <u>Shift downward 4 units </u> i.e.

Subtract 4 from the value of y:

y=-(x-2)^2-4 (Graph 4 in attachments)

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90 is n multiplied by 123 write equation (IXL)
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90 = n * 123

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<h2>Answer:</h2>

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C an anyone solve this 3(2b + 3)2 = 36<br> and if so what is it
Natali [406]
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(2b + 3)^2 = 12

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3 years ago
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Properties of the normal distribution include?
V125BC [204]

Answer:

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Exactly half of the values are to the left of center and exactly half the values are to the right.

The total area under the curve is 1.

Step-by-step explanation:

6 0
3 years ago
A ship leaves port and travels due west for 30 knots, then changes course to S 30° W and travels 50 more knots. Find the bearing
leva [86]

Answer:

  232°

Step-by-step explanation:

There are a couple of ways to find the desired direction. Perhaps the most straightforward is to add up the coordinates of the travel vectors.

  30∠270° +50∠210° = 30(cos(270°), sin(270°)) +50(cos(210°), sin(210°))

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Then the angle from port is ...

  arctan(-55/-43.301) ≈ 231.79° . . . . . . . 3rd quadrant angle

The bearing of the ship from port is about 232°.

_____

<em>Comment on the problem statement</em>

The term "knot" is conventionally used to indicate a measure of speed (nautical mile per hour), not distance. It is derived from the use of a knotted rope to estimate speed. Knots on the rope were typically 47 ft 3 inches apart. As a measure of distance 30 knots is about 1417.5 feet.

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3 years ago
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