PLSSSSSSSSSSSSSSSS HELP PPLLASSSSSSSS

A gardener wants to compare the heights of plants in two gardens that are watered using different tools. The heights, in centime

ryzh [129]

Garden A: 24.05cm ( add all the numbers(=457)and divide by the amount of numbers (19))

Garden B: 22.85cm ( add all numbers (=480) divide by amount of numbers (21))

3 0

3 years ago

A parallel system functions whenever at least one of its components works. Consider a parallel system of 5 components, and suppo

Aneli [31]

Answer:

Probability that component 4 works given that the system is functioning = 0.434 .

Step-by-step explanation:

We are given that a parallel system functions whenever at least one of its components works.

There are parallel system of 5 components and each component works independently with probability 0.4 .

Let <em>A = Probability of component 4 working properly, P(A) = 0.4 .</em>

<em>Also let S = Probability that system is functioning for whole 5 components, P(S)</em>

Now, the conditional probability that component 4 works given that the system is functioning is given by P(A/S) ;

P(A/S) = {Means P(component 4 working and system also working)

divided by P(system is functioning)}

P(A/S) = {In numerator it is P(component 4 working) and in

denominator it is P(system working) = 1 - P(system is not working)}

Since we know that P(system not working) means that none of the components is working in system and it is given with the probability of 0.6 and since there are total of 5 components so P(system working) = 1 - $0.6^{5}$ .

Hence, P(A/S) = $\frac{0.4}{1 - 0.6^{5} }$ = 0.434.

7 0

2 years ago

A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe

PSYCHO15rus [73]

Answer:

Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2 bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let A = (u - E) * ( $\sqrt{n}$ / s) be the test statistic

we want P( average_l < A < average_u ) = 95%

look for lower 2.5% and the upper 97.5% Because I think this is a 2-tail test

average_l = -1.96 which corresponds to the 2.5%

average_u = 1.96

P( -1.96 < A < 1.96) = 95%

P( -1.96 < (u - E) * ( $\sqrt{n}$ / s) < 1.96) = 95%

Solve for the true mean E ok

E < u + 1.96* (s / $\sqrt{n}$ )

from -1.96 < (u - E) * ( $\sqrt{n}$ / s)

E < 26,226.2 + 1.96*( 2,322.32 / $\sqrt{77}$ )

E < 26,226.2 + 518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s / $\sqrt{n}$ ) < E

26,226.2 - 518.7197348105429466 < E

25,707.48026519 < E

lower bound is 25,707.48026519

Therefore the 95% confidence interval is (25,707.480 < E < 26,744.920)

7 0

2 years ago

The distance traveled varies directly with the time of travel. If

never [62]

Answer:

The constant is 10 for every 1 seconds the time traveled is 10 meters

Step-by-step explanation:

7 0

2 years ago

Alpha printing will make 400 brochures for $100. Omega printing will make 1,000 brochures for $100. How much money will you save

Dmitriy789 [7]

it is given in the question that

Alpha printing will make 400 brochures for $100. Omega printing will make 1,000 brochures for $100.

For Alpha, cost of 1 brochure is

$= \frac{100}{400} = $0.25$

For Omega,

Cost of 1 brochure is

$= \frac{100}{1000} = 0.10$

So choosing Omega printing, you will save

$= 0.25-0.10 = $0.15$

on each brochure .

6 0

2 years ago