"2 minus root 3" => 2 - sqrt(3)
x does not appear here. That could cause a problem.
Unsure of what you mean by "x minus one upon X whole cube." Would you please go back to the original question and ensure that you have copied it down precisely. Without "x" in your equation, there's nothing to solve for.
"the argument" of a function, is simply "the expression being evaluated by that function".
Answer:
The last 15 percent of that would be 39
Step-by-step explanation:
Replace the CIRCLES by A and the SQUARES by B:
1) A + B = 14 And
2) A - B = 2
Add 1) + 2)
A+B =14
A-B = 2
------ ----
2A+0 = 16 then A = 16/2 = 8. If A = 8, then B = 6
So the CIRCLE = 8 and the SQUARE = 6
