Answer:
5 1/5
Step-by-step explanation:
6 1/2 *4/5
Rewriting as an improper fraction
( 2*6 +1)/2 *4/5
13/2 *4/5
52/ 10
50/10 + 2/10
5 +1/5
5 1/5
The area of a circle is pi*r^2 so 324/pi is 103 if you take the square root of that it is 10.15. so you would use the circumference formula now, which is 2 pi r so 2*pi*10.15= 63.77
<span>x1+x2+x3=0 if x1,x2,x3 > -5?
and the solutions are integer
x1= - 4 and x2+x3=4 we count (-4;4;0), (-4;0;4), (-4;3;1), (-4;1;3), (-4; 2;2), (-4;2;2)
x1= -3 and x2+x3=3 we count (-3; 0;3), (-3;3;0), (-3;1;2), (-3;2;1)
x1= -2 and x2+x3=2 we count (-2;0;2). (-2;2;0), (-2;1;1)
x1= -1 and x2+x3=1 we count (-1;0;1), (-1;1;0)
x1=0 and (0;0;0), (0;1;-1), (0;-1;1)
There are 42 solutions
Have fun</span>
Answer:
140.04
Step-by-step explanation:
(4.89+5.68+8.91+9.22+6.31)*4 = 140.04
