Answer:
Step-by-step explanation:
According to the table, function g(x) reaches the max height of 33, approx.
The equation of motion is f(x) = -16x^2 + 42x + 12. We need to determine the maximum of this function. To do this, find the x-coordinate of the vertex, which is x = -b/(2a), or x = -42/(2*-16), or 1.31 sec.
Evaluating f(x) = -16x^2 + 42x + 12 at x = 1.31 sec, we get f(1.31) = 39.6.
So it appears that f(x) has a higher max than does g(x); the difference is approx. 39.6 - 33, or 6.6
Answer:
a. 12 minutes
b. 34 minutes
Step-by-step explanation:
Here, we are told that Ima has driven 5 minutes before Polly started driving
So if Ima has driven for x minutes , polly would have driven for y minutes but the difference between x and y is 5
So mathematically;
x = y + 5
a. 17 = y + 5
y = 17-5 = 12 minutes
b. x = 29 + 5
x = 34 minutes
Alternate exterior angles(AEA).
Given their relationship the angles are congruent.
8x-71=5x+7
3x-71=7
3x=78
X=26
Answer:
x= 37.5°
Step-by-step explanation:
∠CBD
= 180° -75° (adj. ∠s on a str. line)
= 105°
∠BCD= ∠BDC (base ∠s of isos. △BCD)
∠BCD= x
∠BCD +∠BDC +∠CBD= 180° (∠ sum of △BCD)
x +x +105°= 180°
2x= 180° -105°
2x= 75°
x= 37.5°
<u>Alternative</u><u> </u><u>working</u><u>:</u>
∠BDA= (180° -75°) ÷2 (base ∠s of isos. △ABD)
∠BDA= 52.5°
∠BDA +∠BDC= 90°
52.5° +x= 90°
x= 90° -52.5°
x= 37.5°
