3 years ago

Hi please someone give me the algebraic expression to this question.

Mathematics

1 answer:

Cloud [144]3 years ago

5 0

Answer:

it is 1

Step-by-step explanation:

the lowest possible integer is 1

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KATRIN_1 [288]

Answer:

Step-by-step explanation:

when you subtact 3y on both sides

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2 years ago

it cost $3.45 to buy 3/4 lb of chopped walnuts how much would it cost to purchase 7.2 lb of walnuts

andreev551 [17]

Answer:

Step-by-step explanation:

$33.12

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3 years ago

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leonid [27]

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3 years ago

ILL GIVE BRAINLEST

bija089 [108]

Answer:

A. 7

<em>good luck, i hope this helps :) </em>

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3 years ago

Read 2 more answers

The sum of 30 times (1/3)^(n-1) from 1 to infinity

sergeinik [125]

Let

$S_n=\displaystyle1+\frac13+\frac1{3^2}+\cdots+\frac1{3^n}$

Then

$\dfrac13S_n=\displaystyle\frac13+\frac1{3^2}+\frac1{3^3}+\cdots+\frac1{3^{n+1}}$

and

$S_n-\dfrac13S_n=\dfrac23S_n=1-\dfrac1{3^{n+1}}\implies S_n=\dfrac32-\dfrac1{2\cdot3^n}$

and as $n\to\infty$ , we end up with

$\displaystyle\lim_{n\to\infty}S_n=\lim_{n\to\infty}\sum_{i=1}^{n+1}\frac1{3^{i-1}}=\lim_{n\to\infty}\left(\frac32-\frac1{2\cdot3^n}\right)=\frac32$

So we have

$\displaystyle\sum_{n=1}^\infty30\left(\frac13\right)^{n-1}=30\cdot\frac32=45$

8 0

3 years ago