Considering that the addresses of memory locations are specified in hexadecimal.
a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ ) = 65536 memory locations
b) The range of hex addresses in a microcomputer with 4096 memory locations is ; 4095
<u>applying the given data </u>:
a) first step : convert FFFF₁₆ to decimal ( note F₁₆ = 15 decimal )
( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )
= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )
= 61440 + 3840 + 240 + 15 = 65535
∴ the memory locations from 0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations
b) The range of hex addresses with a memory location of 4096
= 0000₁₆ to FFFF₁₆ = 0 to 4096
∴ the range = 4095
Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.
Learn more : brainly.com/question/18993173
Answer:
Answer: -7
Step-by-step explanation:
Answer:
1.23
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
37 degrees
Step-by-step explanation:
1. m∠CBA = 71+45 = 116 degrees
2. m∠CBA = m∠CDA because of the quadrilateral property of opposite sides.
3. m∠CBA + m∠CDA = 2*116 = 232.
4. Total angle measure of a quadrilateral is 360 degrees, so m∠BAD + m∠BCD = 360-232 = 128 degrees.
5. m∠BAD = m∠BCD = 128/2 = 64 degrees
6. m∠BAC = m∠BAD - m∠CAD = 64 - 27 = 37 degrees
