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DedPeter [7]
3 years ago
7

Se contrató a un arquitecto para construir un monumento conmemorativo. La estructura sería una pirámide formada con balas de cañ

ón. La base sería un cuadrado hecho con 100 balas, la capa siguiente tendría 81 balas y así se continuaría construyendo. La pregunta es, ¿Cuántas balas se utilizaron para construir el monumento?
Mathematics
1 answer:
PIT_PIT [208]3 years ago
7 0

Answer:

385 balas de cañon

Step-by-step explanation:

la base mide 10 x 10 = 100 balas de cañon

la capa siguiente mide 9 x 9 = 81 balas de cañon

la siguiente 8 x 8 = 64

despues 7 x 7 = 49

luego 6 x 6 = 36

y seguimos adelante con 5 x 5 = 25, 4 x 4 = 16, 3 x 3 = 9, 2 x 2 = 4 y finalmente tenemos 1 sola bala de cañon.

El total de balas de cañon = 100 + 81 + 64 + 49 + 36 +25 + 16 + 9 + 4 + 1 = 385 balas de cañon

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3 years ago
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Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt
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Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

At the null hypothesis, it is <u>tested if it does not outlast by more than 2 hours</u>, that is, the subtraction is not more than 2:

H_0: \mu_B - mu_A \leq 2

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

H_1: \mu_B - \mu_A > 2

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s_{Ea} = S_{Eb} = \frac{0.67}{\sqrt{12}} = 0.1934

The distribution of the difference has <u>mean and standard deviation</u> given by:

\overline{x} = \mu_B - \mu_A = 11.23 - 8.65 = 2.58

s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 2 is the value tested at the hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{2.58 - 2}{0.2735}

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Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

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2 years ago
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2 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

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The diagonals of a rhombus bisect opposite angles.

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You know two sides and the included angle of a triangle.

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x = sq rt 4030.1508...

  =  63.5

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2 years ago
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