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Stella [2.4K]
3 years ago
11

Choose True or False for each equation for x = 6.

Mathematics
2 answers:
vaieri [72.5K]3 years ago
6 0

1 = False (6x6 = 36)

2 = True ( 6 + 5 = 11)

3 = True ( 6/2 = 3)

4 = True (17 - 6 = 11)

Cloud [144]3 years ago
5 0

Answer:

false

true

true

true

Step-by-step explanation:

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Is the answer 3, 4, 5, or 6? need answer asap please! :)
-BARSIC- [3]
Don't touch the center. It is already even. 
Start anywhere by connecting a dotted line from one vertex to the next. To keep things so we know what we are talking about, go clockwise. Now you have 2 points that are Eulerized that were not before.

Skip and edge and do the same thing to the next two vertices. Those two become eulerized. Skip an edge and do the last 2.

Let's try to describe this better. Start at any vertex and number them 1 to 6 clockwise.
Join 1 to 2 
Join 3 to 4
Join 5 to 6

I think 3 is the minimum.
3 <<<< answer
4 0
3 years ago
What is the slope of a line that passes through the points (2,5) and (4,9)
ahrayia [7]

Answer:

2

Step-by-step explanation:

slope = difference of y/ difference of x

m = (9-5) / (4-2) = 4/2 = 2

8 0
3 years ago
9x = 63 what is x<br> <img src="https://tex.z-dn.net/?f=9x%20%3D%2063" id="TexFormula1" title="9x = 63" alt="9x = 63" align="abs
tankabanditka [31]

Answer:

x = 7

Step-by-step explanation:

Please give me brainliest :)

5 0
2 years ago
Round 146,273,011 to the nearest hundred thousand.<br><br> i need help
loris [4]

Answer:

146,300,000

Step-by-step explanation:

146,273,011

<u>The hundred thousand place is 100,000</u>

<u />

<u>Step 1:  Round</u>

146,273,011

<em>146,300,000</em>

<em />

Answer:  146,300,000

6 0
3 years ago
An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from so
alexgriva [62]

Solution :

Let p_1 and p_2  represents the proportions of the seeds which germinate among the seeds planted in the soil containing 3\% and 5\% mushroom compost by weight respectively.

To test the null hypothesis H_0: p_1=p_2 against the alternate hypothesis  H_1:p_1 \neq p_2 .

Let \hat p_1, \hat p_2 denotes the respective sample proportions and the n_1, n_2 represents the sample size respectively.

$\hat p_1 = \frac{74}{155} = 0.477419

n_1=155

$p_2=\frac{86}{155}=0.554839

n_2=155

The test statistic can be written as :

$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}

which under H_0  follows the standard normal distribution.

We reject H_0 at 0.05 level of significance, if the P-value or if |z_{obs}|>Z_{0.025}

Now, the value of the test statistics = -1.368928

The critical value = \pm 1.959964

P-value = $P(|z|> z_{obs})= 2 \times P(z< -1.367928)$

                                     $=2 \times 0.085667$

                                     = 0.171335

Since the p-value > 0.05 and $|z_{obs}| \ngtr z_{critical} = 1.959964$, so we fail to reject H_0 at 0.05 level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the \text{proportion} of the seeds that \text{germinate differs} with the percent of the \text{mushroom compost} in the soil.

8 0
3 years ago
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