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natulia [17]
3 years ago
13

If the area of a triangle is 30 in.? and the base is 5 in., what is the height?

Mathematics
1 answer:
seropon [69]3 years ago
7 0
The height would be 12. This is because the area formula for a triangle is base times height divided by 2.
Therefore 12 x 5 = 60 and 60/2 = 30 :)
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Someone pls help me I'm really struggling and the assignment is almost due
Grace [21]

Answer:

x<3 and x≥5

Step-by-step explanation:

Look at the circles and what is shaded on the number line.  The first circle is at x=3, and it's an open circle.  An open circle means that the interval does not include that point.  The arrow is going to the left, meaning x < 3.

The next circle is at x=5.  It is a closed circle, so the interval does include that point (so draw a bar under the less than/greater than sign).  Next, notice how the arrow is pointing to the right.  That means that the blue area is at x=5 and greater than x=5, so x≥5.

5 0
3 years ago
Determine whether the relation shown is a function. Explain how you know.
lutik1710 [3]

Answer:

  It is not a function

Step-by-step explanation:

The plot shows (1, 1) and (1, 3) are both defined by the relation. It does not pass the "vertical line test", which requires the relation be single-valued everywhere.

3 0
3 years ago
Read 2 more answers
Help help I don’t really get this???
insens350 [35]

Answer:

Question 4:  y=\displaystyle -\frac{4}{5}x

Question 5: y=-5x-3

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where <em>m</em> is the slope of the line and <em>b</em> is the y-intercept (the y-coordinate of the point where the line crosses the y-axis).

<u>Question 4</u>

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

\displaystyle m=\frac{y_2-y_1}{x_2-x_1} where two points that pass through the line are (x_1,y_1) and (x_2,y_2)

In the graph, two easy-to-identify points on the line are (-5,4) and (5,-4). Plug these into the equation:

\displaystyle m=\frac{-4-4}{5-(-5)}\\\\\displaystyle m=\frac{-4-4}{5+5}\\\\\displaystyle m=\frac{-8}{10}\\\\\displaystyle m=-\frac{4}{5}

Therefore, the slope of the line is \displaystyle -\frac{4}{5}. Plug this into y=mx+b as the slope (<em>m</em>):

y=\displaystyle -\frac{4}{5}x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

On the graph, we can see that the line crosses the y-axis when y is 0. Therefore, the y-intercept (<em>b</em>) is 0. Plug this into y=\displaystyle -\frac{4}{5}x+b:

y=\displaystyle -\frac{4}{5}x+0\\\\y=\displaystyle -\frac{4}{5}x

<u>Question 5</u>

<u>1) Determine the slope (</u><u><em>m</em></u><u>)</u>

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

Two easy-to-identify points are (-1,2) and (0,-3). Plug these into the equation:

\displaystyle m=\frac{-3-2}{0-(-1)}\\\\\displaystyle m=\frac{-3-2}{0+1}\\\\\displaystyle m=\frac{-5}{1}\\\\m=-5

Therefore, the slope is -5. Plug this into y=mx+b:

y=-5x+b

<u>2) Determine the y-intercept (</u><u><em>b</em></u><u>)</u>

On the graph, we can see that the line crosses the y-axis at the point (0,-3). The y-coordinate of this point is -3. Therefore, the y-intercept (<em>b</em>) is -3. Plug this into y=-5x+b:

y=-5x+(-3)\\y=-5x-3

I hope this helps!

8 0
2 years ago
Rewrite the equation 2x+8y=16 in slope-intercept form
Shkiper50 [21]
The goal is to solve for y. Start by subtracting 2x from both sides. This gives you 8y=-2x+16. Now just divide both sides by 8, which gives you y=-2/8x+16/8. Finally, simplify this to y=-1/4x+2.
7 0
3 years ago
X+8=17 what is the value of x makes the sentece true​
melisa1 [442]

Answer:

x = 9

Step-by-step explanation:

Step 1: Write equation

x + 8 = 17

Step 2: Solve for <em>x</em>

  1. Subtract 8 on both sides: x = 9

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

9 + 8 = 17

17 = 17

7 0
3 years ago
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