HELP ME!!! Find the area of the composite figure.

Mathematics

2 answers:

spin [16.1K]3 years ago

8 0

Split the figure into two pieces (a triangle and a rectangle)

area of rectangle:
length x width = 20 x 8 = 160

area of triangle:
(base x height)/2 = (20 x 6)/2 = 120/2 = 60

add the two areas:
160 + 60 = 220

answer: 220 square units

hope this helps

VladimirAG [237]3 years ago

4 0

Well basically what you need to do is dta

You might be interested in

Evaluate the expression of 26^3+5 when b=3

arsen [322]

Answer:

i dont knoy sorry i am in hurry

5 0

2 years ago

Read 2 more answers

In ΔJKL, k = 9.6 cm, l = 2.7 cm and ∠J=43°. Find ∠L, to the nearest 10th of a degree.

Bogdan [553]

Answer:

L = 10.64°

Step-by-step explanation:

From the given information:

In triangle JKL;

line k = 9.6 cm

line l = 2.7 cm; &

angle J = 43°

we are to find angle L = ???

We can use the sine rule to determine angle L:

i.e

$\dfrac{j}{SIn \ J} = \dfrac{l}{ SIn \ L}$

Using Pythagoras rule to find j

i,e

j² = k² + l²

j² = 9.6²+ 2.7²

j² = 92.16 + 7.29

j² = 99.45

$j = \sqrt{99.45}$

j = 9.97

∴

$\dfrac{9.97}{Sin \ 43} = \dfrac{2.7}{ Sin \ L}$

${9.97 \times Sin (L ) = (2.7 \times Sin \ 43)$

$= Sin \ L = \dfrac{ (2.7 \times Sin \ 43)}{9.97 } \\ \\ = Sin \ L = \dfrac{ (2.7 \times 0.6819)}{9.97 } \\ \\ = Sin \ L = 0.18466 \\ \\ L = Sin^{-1} (0.18466) \\ \\ L = 10.64 ^0$