Factor the coefficients:
-12=(-1)(3)(2^2)
-9=(-1)(3^2)
3=3
The greatest common factor (GCF) is 3
Next we find the GCF for the variable x.
x^4
x^3
x^2
The GCF is x^2.
Next GCF for variable y.
y
y^2
y^3
the GCF is y
Therefore the GCF is 3x^2y
To factor this out, we need to divide each term by the GCF,
(3x^2y)(−12x4y/(3x^2y) − 9x3y2/(3x^2y) + 3x2y3/(3x^2y) )
=(3x^2y)(-4x^2-3xy+y^2)
if we wish, we can factor further:
(3x^2y)(y-4x)(x+y)
Answer:
who?
Step-by-step explanation:
Answer:
20
Step-by-step explanation:
ones= 1
tens= 10
Hundreds= 100
The difference between ones and tens is the 0. ones=1. tens=10
<u>2</u>4
The 2 is in the beginning so its the 10's place. The 4 is the second number so its in the ones place
From the statement of the problem, we know that:
• a train starts at City A and travels 2,158 km to City B,
,
• then it travels 3,793 km from City B to City C.
The distance between City A and City C is equal to the sum of the distance from City A to City B, and the distance from City B to City C. So the distance between City A and City C is 2,158 km + 3,793 km = 5951 km.
Looking at the answer of Clay:
<em>2,158 + 3,793 = (2,158 + 7) + (3,793 + 7) = 2,165 + 3,800 = 5,965</em>
We see that he added 7 km to each of the distances, that's the reason why he found a different a wrong result.
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
brainly.com/question/28048895
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