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3 years ago

10

Alexis saves up her monthly allowance over a period of six months to buy a pair of high-resolution headphones. She lends her fri

end, Janet $32.80 from her savings. If Alexis has $216.20 now, calculate her monthly allowance.

2 answers:

Anika [276]3 years ago

6 0

Her monthly allowance should be $41.50

tino4ka555 [31]3 years ago

5 0

Answer:

$41.50

Step-by-step explanation:

:))) please mark me brainliest!

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A triangle has sides of (2x), (x - 7) and (3x - 20).

LiRa [457]

2x+x-7+3x-20=87cm
6x-27=87
6x=114
x=19
Therefore the sides are:12cm, 38cm, and 37cm

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3 years ago

Please help on all asap, tysm <33

kondor19780726 [428]

Answer:

1. 4.22

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Step-by-step explanation

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2 years ago

I need help with letter A

zhannawk [14.2K]

Answer:

14

Step-by-step explanation:

the four smaller rectangles of each of the corners: 2*1=2. since there are four of them, 2*4=8

the middle, larger rectangle: (6-2-2)*(1+1+1) = 2*3 =6

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3 0

2 years ago

Read 2 more answers

Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. (a) Descri

OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

$\mu = 74$

and

$\sigma = 6$

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

$\mu = 74$

The standard error of the means becomes the standard deviation of the sampling distribution.

$\sigma_ { \bar X } = \frac{ \sigma}{ \sqrt{n} } \\ \sigma_ { \bar X } = \frac{ 6}{ \sqrt{36} } = 1$

Part b) We want to find

$P(\bar X \:>\:75.9)$

We need to convert to z-score.

$P(\bar X \:>\:75.9) = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: \frac{75.9 - 74}{1} ) \\ = P(z \:>\: 1.9) \\ = 0.0287$

Part c)

We want to find

$P(\bar X \: < \:71.95)$

We convert to z-score and use the normal distribution table to find the corresponding area.

$P(\bar X \: < \:71.95) = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: \frac{71.9 5- 74}{1} ) \\ = P(z \: < \: - 2.05) \\ = 0.0202$

Part d)

We want to find :

$P(73\:$

We convert to z-scores and again use the standard normal distribution table.

$P( \frac{73 - 74}{1} \:< \: z$

5 0

3 years ago

Can someone help me with math

kkurt [141]

A is the correct answer, I believe.

7 0

2 years ago

Read 2 more answers