Triangle XYZ has points X = (–4,4), Y = (0,1), and Z = (4,4). Triangle X'Y'Z' has points X ’= (–5,–4), Y’ = (–1,–1), Z’ = (3,–4)
Rama09 [41]
So they moved down one and reflected over the y axis
Answer:
p(x)= (x+1)(x+2)(x-3)(x-1)
then,multiplying two two terms
(x^2 +2x+x+2)(x^2-x-3x+3)
(x^2+3x+2)(x^2-4x+3)
x^4- 4x^3+3x^2 +3x^3-12x^2+9x+2x^2-8x+6)
x^4-x^3-7x^2+x+6
You can make it easier by replacing x^n with another variable, factoring, then putting x^n back in the end.
Using exponent and algebra rules, rewrite x^2n - 2x^n + 1 as
(x^n)^2 - (2 x x^2) + 1
Then, let x^n = m.
m^2 - 2m + 1
Now factor that: (m - 1)^2
And now put x^n back: (x^n - 1)^2
Answer: 
Step-by-step explanation:
We need to use the following formula to find the Midpoint "M":
Given the points (-5,13) and (6,4) can identify that:
The final step is to substitute values into the formula.
Therefore, the midpoint of the segment between the points (-5,13) and (6,4) is:
