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There are 2 Senators from each of 50 states. We wish to make a 3-Senator committee in which no two members are from the same sta

LenaWriter [7]

Answer:

940800 different ways to create the committee.

Step-by-step explanation:

1 chosen from 100 leaves 98 to chose from on the second pick because the other senator from the same state is also eliminated. The second choice leaves 96 available for the third selection.

So multiply 100×98×96=940800

5 0

3 years ago

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What is the slope below

enyata [817]

Answer:

Step-by-step explanation:

Tyyh

7 0

3 years ago

A line with the equation y = x and a circle with the

Alik [6]

Step-by-step explanation:

4 0

3 years ago

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Question 19 of 25

Ronch [10]

The next step in the series will be Option B

<h3>What is a Series ?</h3>

A series is the sequence of object in pattern.

From the given figure it can be seen that the red and blue colour semicircle are shifting alternately , and the number series is increasing by 1

Therefore the next step is red on the right side , blue on the left side and no. 4 written on blue

Therefore Option B is the right answer.

To know about Series

brainly.com/question/15415793

#SPJ1

4 0

2 years ago

Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{

SVETLANKA909090 [29]

$y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\$

$\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\$

This shows that $y' = y$ is true when $y = e^x$

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Note 1: A more general solution is $y = Ce^x$ for some constant C.
Note 2: It might be tempting to say the general solution is $y = e^x+C$ , but that is not the case because $y = e^x+C \to y' = e^x+0 = e^x$ and we can see that $y' = y$ would only be true for C = 0, so that is why $y = e^x+C$ does not work.

6 0

3 years ago