Answer:
Yes
Step-by-step explanation:
Yes it is possible to solve a quadratic equation that is not factorable over the set of integers.
The solution may vary like Integers, rationals, irrationals or complex solutions.
To find two roots of the equation we can always use the formula given below to solve a quadratic equation,
For the quadratic equation,
, we have,
If the discriminant is greater than 
, we get complex roots.
We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
Let
A------> Lincoln, NE
B------> Boulder, CO
C------> third city
we know that
in the triangle ABC
AB=500 miles
BC=200 miles
AC=x
Applying the Triangle Inequality Theorem
1) 500+200 > x------> 700 > x------> x < 700 miles
2) 200+x > 500----> x > 500-200------> x > 300 miles
the solution for x is
300 < x < 700
the interval is------> (300,700)
the possible distances, d, in miles, between Lincoln, NE, and the third city, are in the range between 300 and 700 miles
P = 2(L + W)
P = 264
W = 54
264 = 2(L + 54)
264 = 2L + 108
264 - 108 = 2L
156 = 2L
156/2 = L
78 <=== Length is 78 yards
Answer:
7+√5/4
Step-by-step explanation:
if that is = a, find the value of a + 1 over a
Given that a = 3 - √5
a+1/1 = (3-√5)+1/3 - √5
4-√5/3 - √5
Rationalize
4-√5/3 - √5 * 3+√5/3 + √5
= 12 +4√5-3√5-√25/9-5
= 12+√5-5/4
= 7+√5/4
Hence the requred answer is 7+√5/4
Answer:
4
Step-by-step explanation:
The equation to find the intercept is m = y2 - y2 / x2 - x1
If we plus in the values the equation would be 1 + 11 / -2 - 5
Solve form there and you get: m = 4
Therefore the answer is 4.
