Divide by 10 both sides and you get a=4
Answer:
![\frac{\sqrt{x} }{2x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7Bx%7D%20%7D%7B2x%7D)
Step-by-step explanation:
Rationalize the denominator first (keep in mind we are NOT solving this because there is no equals sign here. We are merely simplifying.)
![\frac{\sqrt{5x} }{x\sqrt{20} } *\frac{\sqrt{20} }{\sqrt{20} } =\frac{\sqrt{100x} }{20x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B5x%7D%20%7D%7Bx%5Csqrt%7B20%7D%20%7D%20%2A%5Cfrac%7B%5Csqrt%7B20%7D%20%7D%7B%5Csqrt%7B20%7D%20%7D%20%3D%5Cfrac%7B%5Csqrt%7B100x%7D%20%7D%7B20x%7D)
Now simplify by taking the square root of 100 to get:
![\frac{10\sqrt{x} }{20x}](https://tex.z-dn.net/?f=%5Cfrac%7B10%5Csqrt%7Bx%7D%20%7D%7B20x%7D)
Divide numerator and denomiator by 10 to get:
![\frac{\sqrt{x} }{2x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7Bx%7D%20%7D%7B2x%7D)
Answer:
4.1 billion
Step-by-step explanation:
1 ft = 30.48 cm
1 in = 2.54 cm
The volume of rain that fell on the roof is given by ...
V = LWH
V = (175 ft × 30.48 cm/ft)(45 ft × 30.48 cm/ft)(11 in × 2.54 cm/in)
= 175×45×11×30.48²×2.54 cm³ = 204,412,236.336 cm³
At 20 drops per cm³, this will be ...
20×204,412,236.336 ≈ 4,088,244,727 . . . . raindrops
About 4.1 billion raindrops fell on your roof.
In a right triangle, the hypotenuse is √2 x the legs. In this case, the value of x is
.
Answer:
The scatter diagram that contains the correlation coefficient closest to r = 1 is the first one shown in the attached images.
Step-by-step explanation:
The correlation coefficient "r" measures how much two variables x and y are related. When the variables are highly related, the value of r is closer to one and the points contained in the scatter diagrams are assimilated more and more to a line. When the value of r is positive the relation is crescent and therefore the slope of the line drawn by the points in the diagram has a positive slope
Therefore, to answer this question, one must search among the attached images for the dispersion diagram in which the points resemble a straight line with a positive slope.
The scatter diagram that meets the requirements mentioned is the first one that appears in the attached images