Factor completely 50a2b5 − 35a4b3 + 5a3b4

Anuta_ua [19.1K]

Answer:

Explanation:

$\sqrt[a]{ {x}^{n} } = {x}^{ \frac{n}{a} } \\ \sqrt[7]{ {53}^{3} } = {(53}^{3} ) {}^{ \frac{1}{7} } \\ \: \: \: \: \: \: \: \: \: \: \: = {53}^{ \frac{3}{7} } \\ comparing \: with \: {53}^{ \frac{a}{b} } \\ a = 3$

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3 0

4 years ago

Ron has a model car. The scale of the model to the actual car is 1:10. The length of the model car is 15 inches. How long is the

natita [175]

150 inches
1:10=15:150

7 0

4 years ago

Read 2 more answers

The Skittles jar has a radius of 3.5 cm and a height of 11.5 cm. Using the two given boxes for reference what would be a good es

nevsk [136]

Answer:

1052

Step-by-step explanation:

The two given boxes for reference are presented below.

Since we know the dimensions of the first container, we can calculate its volume.

$V_1= 5 \text{cm} \cdot 4 \text{cm} \cdot 4 \text{cm} = 80 \text{cm}^3$

The first container held 192 skittles. Using that fact, now that we know the volume of the first box, we can calculate the volume of a single skittle.

$v = \frac{80}{192} = 0.416 \approx 0.42 \text{cm}^3$

The second container held 258 skittles.

The volume of the second box is:

$V_2 = 12 \text{cm}\cdot 3 \text{cm} \cdot 3 \text{cm} = 108 \text{cm}^3$

Using this facts, the volume of a single skittle would be

$v = \frac{108}{258} = 0.418 \approx 0.42 \text{cm}^3$

Therefore, the volume of single skittle is around to 0.42 cm³.

A skittle jar is a cylinder. Its volume is calculated by the formula

$V = r^2h \pi$ ,

where $r$ is the radius and $h$ is the height. From the given data, we have $r = 3.15 \text{cm}$ and $h = 11.5 \text{cm}$ . Hence, the volume of the jar is