Answer:
75%
Step-by-step explanation:
try this answer
Answer:
y = -5/2x - 13
Step-by-step explanation:
First, we have to find the slope of the original equation
Subtract 5x from both sides
5x + 2y = 1
- 5x - 5x
2y = -5x + 1
Divide both sides by 2
2y/2 = (-5x + 1)/2
y = -5/2x + 1/2
The slope of this equation is -5/2, so -5/2 has to be in our new parallel equation
y = -5/2x + b
Plug in the given x and y
-3 = -5/2(-2) + b
-3 = 10 + b
Subtract 10 from both sides
-3 = 10 + b
- 10 - 10
b = -13
This makes our equation: y = -5/2x - 13
Answer:
Part 1) Option D. must be an acute angle
Part 2) m∠A=70°
Step-by-step explanation:
Part 1) In triangle ABC, if an exterior angle drawn at vertex C measures 45, then angle B...
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
The measure of an exterior angle at C is equal to the sum of the interior angles at A and B
we have that
45°=m∠A+m∠B
therefore
m∠B < 90°
Angle B must be an acute angle
Part 2)
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
The measure of an exterior angle at B is equal to the sum of the interior angles at A and C
m∠A+m∠C=2m∠C+5
m∠C=m∠A-5 ----> equation A
m∠C=65° ----> equation B
substitute equation B in equation A
65°=m∠A-5
m∠A=(65+5)°=70°
