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2 years ago

Please I need some answers

Mathematics

1 answer:

hichkok12 [17]2 years ago

5 0

a is answer please tell brinlest answer

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What is the solution to this equation x+ 3 2/3= 26

jenyasd209 [6]

Answer:

Exact form : x = 67/3

Decimal form : x = 22.33333333333...

Mixed Number form : x = 22 1/3

Step-by-step explanation: Solve for x by simplifying both sides of the equation, then isolating the variable.

I hope this helps you out. :)

5 0

3 years ago

Given f(x) = x^2 + x − 2 and g(x) = 2x − 4, identify (f + g)(x).

shutvik [7]

Answer:

(f + g)(x) = x^2 + 3x - 6

Step-by-step explanation:

Given f(x) = x^2 + x − 2 and g(x) = 2x − 4

Plug in:

(f + g)(x) = x^2 + x − 2 + 2x − 4

(f + g)(x) = x^2 + 3x - 6

3 0

2 years ago

Read 2 more answers

How far can a person run in 15 minutes if he or she runs at an average speed of 16 km/hr? (Convert minutes into hours)

kykrilka [37]

60/15 is 4
16/4 is 4
in 15 minutes, he or she runs 4km
4 times .621 is about 2.5 miles
hope this helps:)

4 0

2 years ago

Read 2 more answers

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

4 0

3 years ago

Please help and thank you

Fantom [35]

Answer:

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers