1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
natulia [17]
3 years ago
9

The table below shows the number of fish in four lakes with weights in various ranges. The weights of the fish in which lake rep

resent a U-shaped distribution? Weight of fish Lake A Lake B Lake C Lake D Greater than 1 lb but less than 2 lb 2033 2976 1022 1393 Greater than 2 lb but less than 3 lb 2361 2341 1356 1572 Greater than 3 lb but less than 4 lb 2667 1999 1789 1905 Greater than 4 lb but less than 5 lb 2344 2268 1403 1496 Greater than 5 lb but less than 6 lb 2101 2890 1157 1288
Mathematics
2 answers:
olga2289 [7]3 years ago
7 0

Answer:

the answer is lake c

Step-by-step explanation:

i took apex and told me lake c is the answer


Llana [10]3 years ago
3 0

When you plot the numbers on a graph or draw a histogram using them, you find the distribution shapes are


Lake A: ∩

Lake B: ∪

Lake C: ∩

Lake D: ∩


Apparently the weights of fish in Lake B have a U-shaped distribution.

You might be interested in
PLS help. 30 points and brainliest
iren2701 [21]
What is angle A’s equation
8 0
3 years ago
Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m
Elenna [48]

Answer:

Part a: <em>The probability of no arrivals in a one-minute period is 0.000045.</em>

Part b: <em>The probability of three or fewer passengers arrive in a one-minute period is 0.0103.</em>

Part c: <em>The probability of no arrivals in a 15-second is 0.0821.</em>

Part d: <em>The probability of at least one arrival in a 15-second period​ is 0.9179.</em>

Step-by-step explanation:

Airline passengers are arriving at an airport independently. The mean arrival rate is 10 passengers per minute. Consider the random variable X to represent the number of passengers arriving per minute. The random variable X follows a Poisson distribution. That is,

X \sim {\rm{Poisson}}\left( {\lambda = 10} \right)

The probability mass function of X can be written as,

P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots

Substitute the value of λ=10 in the formula as,

P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{{\left( {10} \right)}^x}}}{{x!}}

​Part a:

The probability that there are no arrivals in one minute is calculated by substituting x = 0 in the formula as,

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}}\\\\ = {e^{ - 10}}\\\\ = 0.000045\\\end{array}

<em>The probability of no arrivals in a one-minute period is 0.000045.</em>

Part b:

The probability mass function of X can be written as,

P\left( {X = x} \right) = \frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}};x = 0,1,2, \ldots

The probability of the arrival of three or fewer passengers in one minute is calculated by substituting \lambda = 10λ=10 and x = 0,1,2,3x=0,1,2,3 in the formula as,

\begin{array}{c}\\P\left( {X \le 3} \right) = \sum\limits_{x = 0}^3 {\frac{{{e^{ - \lambda }}{\lambda ^x}}}{{x!}}} \\\\ = \frac{{{e^{ - 10}}{{\left( {10} \right)}^0}}}{{0!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^1}}}{{1!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^2}}}{{2!}} + \frac{{{e^{ - 10}}{{\left( {10} \right)}^3}}}{{3!}}\\\\ = 0.000045 + 0.00045 + 0.00227 + 0.00756\\\\ = 0.0103\\\end{array}

<em>The probability of three or fewer passengers arrive in a one-minute period is 0.0103.</em>

Part c:

Consider the random variable Y to denote the passengers arriving in 15 seconds. This means that the random variable Y can be defined as \frac{X}{4}

\begin{array}{c}\\E\left( Y \right) = E\left( {\frac{X}{4}} \right)\\\\ = \frac{1}{4} \times 10\\\\ = 2.5\\\end{array}

That is,

Y\sim {\rm{Poisson}}\left( {\lambda = 2.5} \right)

So, the probability mass function of Y is,

P\left( {Y = y} \right) = \frac{{{e^{ - \lambda }}{\lambda ^y}}}{{y!}};x = 0,1,2, \ldots

The probability that there are no arrivals in the 15-second period can be calculated by substituting the value of (λ=2.5) and y as 0 as:

\begin{array}{c}\\P\left( {X = 0} \right) = \frac{{{e^{ - 2.5}} \times {{2.5}^0}}}{{0!}}\\\\ = {e^{ - 2.5}}\\\\ = 0.0821\\\end{array}

<em>The probability of no arrivals in a 15-second is 0.0821.</em>

Part d:  

The probability that there is at least one arrival in a 15-second period is calculated as,

\begin{array}{c}\\P\left( {X \ge 1} \right) = 1 - P\left( {X < 1} \right)\\\\ = 1 - P\left( {X = 0} \right)\\\\ = 1 - \frac{{{e^{ - 2.5}} \times {{2.5}^0}}}{{0!}}\\\\ = 1 - {e^{ - 2.5}}\\\end{array}

            \begin{array}{c}\\ = 1 - 0.082\\\\ = 0.9179\\\end{array}

<em>The probability of at least one arrival in a 15-second period​ is 0.9179.</em>

​

​

7 0
3 years ago
Because of variability in the manufacturing process, the actual yielding point of a sample of mild steel subjected to increasing
Alex73 [517]

Answer:

modify tge production

Step-by-step explanation:

7 0
3 years ago
The ratio of boys to girls in Mr. Hoda's art
SOVA2 [1]

Answer:

15:10

Step-by-step explanation:

Method 1: 5 lots of 3:2 →5 × (3:2) = (5×3) : (5×2) = 15:10

Method 2: 3/2 × 1 → 3/2 ×5/5 = 3×5 2×5= 15:10

boys: 15

girls: 10

3 0
3 years ago
A car dealership purchased a car for $15,000. They mark up the price by 35%. What is the retail price of the vehicle
Snowcat [4.5K]

Answer: the answer is 20,250

Step-by-step explanation:

35% of 15,000 = 5,250

15,000+5250 = 20,250

4 0
3 years ago
Other questions:
  • A horse is tied with rope in the center of grassland to graze. The length of the rope is 5m. The diameter of the circular garden
    15·1 answer
  • Which characteristics describe the scatterplot? Check all that apply.
    5·2 answers
  • The letter a represents a nonzero constant. Solve x + a = 3/4<br> for x
    9·2 answers
  • Write and equation ( and maybe solve) please!
    8·1 answer
  • What is the explanation 25 letters in five days
    8·2 answers
  • What is the value of x in the equation 3/5(x+2)=x-4
    15·1 answer
  • PLEASE I NEED HELP AND EXPLAIN PLZ ​
    11·1 answer
  • Which is data distribution that is skewed right
    6·2 answers
  • 10.3.23
    6·1 answer
  • X + 8 = -15<br> What does x= ???
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!