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3 years ago

Write 7/20 as a percent. By what factor should you multiply the denominator and numerator?

Mathematics

2 answers:

levacccp [35]3 years ago

6 0

Answer:

35%

Step-by-step explanation:

Use photomath it tells you everything.

andreyandreev [35.5K]3 years ago

5 0

Answer:

You should multiply the numerator and the denominator by 5. 35%

Step-by-step explanation:

7/20*5/5=35/100

35%

To get from fraction to percent you need the denominator to be 100. To get the denominator 20 to 100 you need to multiply by 5. Then we just take the numerator and add a percent symbol.

You should multiply the numerator and the denominator by 5. 35%

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Peyton is 11 years old and knows 10-7=3 and 3+7=10 but finds it difficult to solve a math problem, such as 3x-5, because she can

Colt1911 [192]

Answer:

concrete operational stage

Step-by-step explanation:

Have a look at the attached photo below, it may be your full question:

The concrete operational stage is the third phase in Piaget's cognitive development theory. This period spans the period between childhood, it begins around 7 years of age and continues until about 11 years of age and is characterized by the development of logical thinking.

7 0

2 years ago

I don't understand please help

kirill [66]

Answer:2x+30 =90

If the angle is 90° altogether

60=A 30=30

Step-by-step explanation:

2x+30 =90

-30 -30

2x=60

÷2. ÷2

x=30

2*30=60

60+30=90

60=A B=30

5 0

2 years ago

A³b² a²b simplify the following expression

liberstina [14]

Answer:

$a^{5}$ $b^{3}$

Step-by-step explanation:

The law of indices can be used to simplify mathematical expressions involving arithmetical operation on variables with powers.

$a^{m}$ x $a^{n}$ = $a^{(m+n)}$

Thus, the given expression can be simplified as follows:

a³b² a²b = a³ x a² x b² x $b^{1}$

= $a^{3+2}$ x $b^{2+1}$

= $a^{5}$ $b^{3}$

Thus,

a³b² a²b = $a^{5}$ $b^{3}$

7 0

2 years ago

What is the quadratic formula?

Ne4ueva [31]

Answer:

I guess u want to know the quadratic function and its formula is, AX*2 + BX + C. Otherwhise you want to know how to get 0 and get the Xm if you want to know how to solve a quadratic. That formula is, (-B +/- $\sqrt{x}$ (B*2 - 4AC) ) . 1/2 (where A, B and C are the number at the original function).

Step-by-step explanation:

6 0

2 years ago

The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth

Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = $P(Laptop) = p_{X} = \frac{4}{9}$

The probability of selecting a desktop is = $P(Desktop) = p_{Y} = \frac{5}{9}$

Then both X and Y follows Binomial distribution.

$X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})$

The probability function of a binomial distribution is:

$P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}$

(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: ${n\choose k}=\frac{n!}{k!(n-k)!}$

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

${8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70$

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

$P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\ =0.304832\\\approx0.305$

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

$P(Y\geq 3)=1-P(Y$

Thus, the probability that at least three of the selected computers are desktops is 0.401.

6 0

2 years ago