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3 years ago

Write 7/20 as a percent. By what factor should you multiply the denominator and numerator?

Mathematics

2 answers:

levacccp [35]3 years ago

6 0

Answer:

35%

Step-by-step explanation:

Use photomath it tells you everything.

andreyandreev [35.5K]3 years ago

5 0

Answer:

You should multiply the numerator and the denominator by 5. 35%

Step-by-step explanation:

7/20*5/5=35/100

35%

To get from fraction to percent you need the denominator to be 100. To get the denominator 20 to 100 you need to multiply by 5. Then we just take the numerator and add a percent symbol.

You should multiply the numerator and the denominator by 5. 35%

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2 years ago

Jim rented a truck for one day. There was a base fee of $18.95 , and there was an additional charge of 78 cents for each mile dr

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3 years ago

Each year for 4 years, a farmer increased the number of trees in a certain orchard by of the number of trees in the orchard the

Neko [114]

Answer:

The number of trees at the begging of the 4-year period was 2560.

Step-by-step explanation:

Let’s say that x is number of trees at the begging of the first year, we know that for four years the number of trees were incised by 1/4 of the number of trees of the preceding year, so at the end of the first year the number of trees was $x+\frac{1}{4} x=\frac{5}{4} x$ , and for the next three years we have that

Start End

Second year $\frac{5}{4}x$ -------------- $\frac{5}{4}x+\frac{1}{4}(\frac{5}{4}x) =\frac{5}{4}x+ \frac{5}{16}x=\frac{25}{16}x=(\frac{5}{4} )^{2}x$

Third year $(\frac{5}{4} )^{2}x$ ------------- $(\frac{5}{4})^{2}x+\frac{1}{4}((\frac{5}{4})^{2}x) =(\frac{5}{4})^{2}x+\frac{5^{2} }{4^{3} } x=(\frac{5}{4})^{3}x$

Fourth year $(\frac{5}{4})^{3}x$ -------------- $(\frac{5}{4})^{3}x+\frac{1}{4}((\frac{5}{4})^{3}x) =(\frac{5}{4})^{3}x+\frac{5^{3} }{4^{4} } x=(\frac{5}{4})^{4}x.$

So the formula to calculate the number of trees in the fourth year is

$(\frac{5}{4} )^{4} x,$ we know that all of the trees thrived and there were 6250 at the end of 4 year period, then

$6250=(\frac{5}{4} )^{4}x$ ⇒ $x=\frac{6250*4^{4} }{5^{4} }= \frac{10*5^{4}*4^{4} }{5^{4} }=2560.$

Therefore the number of trees at the begging of the 4-year period was 2560.

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3 years ago

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just olya [345]

Answer:

$918 is her down payment

Step-by-step explanation:

.18×5100

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3 years ago

A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with milli

skelet666 [1.2K]

Complete Question:

A manufacturer produces piston rings for an automobile engine. It is known that ring diameter is normally distributed with ? = 0.001 millimeters. A random sample of 15 rings has a mean diameter of \bar{X}= 74.106. Construct a 99% two-sided confidence interval on the true mean piston diameter and a 95% lower confidence bound on the true mean piston diameter.

(Round your answers to 3 decimal places.)

(Calculate the 99% two-sided confidence interval on the true mean piston diameter.

Answer:

99% true sided confidence Interval on the true mean Piston diameter = (74.105, 74.107)

Step-by-step explanation:

Check the attached file for the complete solution

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3 years ago