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mash [69]
3 years ago
13

If triangle RST is within Quadrant 4 and cos R= √3/2, what is the value of cotR

Mathematics
1 answer:
Nesterboy [21]3 years ago
6 0

Answer:

CotR = -√3

Step-by-step explanation:

In the 4th quadrant, sin is negative;

Since Cos R = √3/2,

Adjacent = √3

Hypotenuse = 2

Get the opposite;

opp^2 = 2^2 -(√3)^2

opp^2 = 4 - 3

opp^2 = 1

Opp = 1

Get sinR

Sin R = opp/hyp

SinR=  -1/2

CotR = cosR/sinR

CostR = (√3/2)/(-1/2)

CotR = √3/2* -2/1

CotR = -√3

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KonstantinChe [14]
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3 years ago
[HELP PLEASE ALGEBRA] <br><br> Would the answer only be B?
Salsk061 [2.6K]
Hello,

|x+4|=3x-5
if x+4>=0 then
          |x+4|=x+4
          x+4=3x-5
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            x=9/2
else
    x+4<0 : x<-4
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end if


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3 years ago
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xxMikexx [17]

Answer:

1%

Step-by-step explanation:

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Method 1

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$50

$50.50

​

=

\,\,1.01

1.01

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\,\,\color{darkviolet}{101\%}

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​

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