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3 years ago

Find the volume of the cube below

Mathematics

1 answer:

Reptile [31]3 years ago

3 0

The answer to this question is 27

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If PQ bisects Angle RPS and measure of angle RPS = 120°, find p and measure of angle RPQ.

Ghella [55]

Answer:

p = 6; RPQ = 60 degrees

Step-by-step explanation:

Because RPS is 120 degrees and it is bisected by PQ (cut into 2 equal parts), we can determine that both sides are 60 degrees. Set the expression 5p+30 equal to 60 to find the value of p.

5p + 30 = 60

5p = 30

p = 6

So now you have determined that p = 6, and the measure of RPQ is 60 degrees.

Hope this helped!

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3 years ago

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Kevin plans to watch 3 movies each month. Write an equation to represent the total number of movies n that he will watch in m mo

GREYUIT [131]

Answer:

Step-by-step explanation:

n = 3m

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3 years ago

44 +9X3- 35 x 60-20

Roman55 [17]

Answer: -2049. Explanation: Use PEMDAS to solve the equation (parenthesis, exponents, multiplication/division, and addition/subtraction). First multiply the numbers that are being multiplied. You should get 44 + 27 - 2100 - 20. Now start from the beginning, and either add or subtract. The answer is -2049.

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3 years ago

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Solve. Good luck! Please do not try to google this.

Elena L [17]

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$\frac{x(x) + x(2) - 1(x) - 1(2)}{3x(x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{x(x + 2) - 1(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$3x(2x - 1)(2\sqrt{2x} + 3x^{2}) = 2(x + 2)(x - 1)$
$3x(2x(2\sqrt{2x} + 3x^{2}) - 1(2\sqrt{2x} + 3x^{2}) = 2(x(x - 1) + 2(x - 1))$
$3x(2x(2\sqrt{2x}) + 2x(3x^{2}) - 1(2\sqrt{2x}) - 1(3x^{2})) = 2(x(x) - x(1) + 2(x) - 2(1)$
$3x(4x\sqrt{2x} + 6x^{3} - 2\sqrt{2x} - 3x^{2}) = 2(x^{2} - x + 2x - 2)$
$3x(4x\sqrt{2x} - 2\sqrt{2x} + 6x^{3} - 3x^{2}) = 2(x^{2} + x - 2)$
$3x(4x\sqrt{2x}) - 3x(2\sqrt{2x}) + 3x(6x^{3}) - 3x(3x^{2}) = 2(x^{2}) + 2(x) - 2(2)$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} + 18x^{4} - 9x^{3} = 2x^{2} + 2x - 4$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} = -18x^{4} + 9x^{3} + 2x^{2} + 2x - 4$
$6x\sqrt{2x}(2x) - 6x\sqrt{2x}(1) = -9x^{3}(2x) - 9x^{3}(-1) + 2(x^{2}) + 2(x) - 2(2)$
$6x\sqrt{2x}(2x - 1) = -9x^{3}(2x - 1) + 2(x^{2} + x - 2)$

5 0

4 years ago

For the equation 3(2x − 5) = 6x + k, which value of k will create an equation with infinitely many solutions?

WINSTONCH [101]

Answer:

3(2x-5)=6x+k

6x-15=6x+k

6x-6x=k+15

0=k+15

k=-15

Step-by-step explanation:

3 0

3 years ago