The new software organization requires a new point of sale and stock control system for their many stores throughout Pakistan to
1 answer:
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Answer:
Explanation:
The following code is written in Java. It creates 5 random integers and saves them to a list called myList. Then it loops through that list and checks each one until the largest and smallest values are obtained. Finally, it uses these values to calculate the sums and products as requested. The program has been tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Random;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Random rand = new Random();
ArrayList<Integer> myList = new ArrayList<>();
for (int i = 0; i< 5; i++) {
int mynum = rand.nextInt(20);
myList.add(mynum);
}
int largest = myList.get(0);
int smallest = myList.get(0);
int sum = 0;
int product = 1;
int sumLargestandSmallest, productLargestandSmallest;
for (int x : myList) {
if (x > largest) {
largest = x;
}
if (x < smallest) {
smallest = x;
}
sum += x;
product *= x;
}
sumLargestandSmallest = largest + smallest;
productLargestandSmallest = largest * smallest;
System.out.println("List" + Arrays.toString(myList.toArray()));
System.out.println("Smallest: " + smallest);
System.out.println("Largest: " + largest);
System.out.println("Sum: " + sum);
System.out.println("Product: " + product);
System.out.println("Sum of Smallest and Largest: " + sumLargestandSmallest);
System.out.println("Product of Smallest and Largest: " + productLargestandSmallest);
}
}
Answer:
The gates required to build a half adder are :
- AND Gate for Carry.
- XOR Gate for Sum
Explanation:
AND Gate is required for the carry and the XOR gate is required for the sum.
The figures for the gates and the truth tables for the half adder are attached so please refer them for further explanation.
The sum is 1 when one of the input is High or 1 if both the inputs are same then the sum is 0.So this behavior is implemented by X-OR gate.
The carry is High only when both of the inputs are 1.This is implemented by AND-Gate.
