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anastassius [24]
3 years ago
13

No links it’s just a normal question about iPhones.

Computers and Technology
1 answer:
3241004551 [841]3 years ago
7 0

Uh, no?

You will still receive texts from that person if they send you texts.

Deleting the conversation does not affect them being able to text you at all.

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A proper divisor of a positive integer $n$ is a positive integer $d < n$ such that $d$ divides $n$ evenly, or alternatively i
juin [17]

Answer:

The program written in Python is as follows:

<em>See Explanation section for line by line explanation</em>

for n in range(100,1000):

     isum = 0

     for d in range(1,n):

           if n%d == 0:

                 isum += d

     if isum == n * 2:

           print(n)

Explanation:

The program only considers 3 digit numbers. hence the range of n is from 100 to 999

for n in range(100,1000):

This line initializes sum to 0

     isum = 0

This line is an iteration that stands as the divisor

     for d in range(1,n):

This line checks if a number, d can evenly divide n

           if n%d == 0:

If yes, the sum is updated

                 isum += d

This line checks if the current number n is a double-perfect number

     if isum == n * 2:

If yes, n is printed

           print(n)

<em>When the program is run, the displayed output is 120 and 672</em>

4 0
3 years ago
Sentence Deobfuscate Name this file deobfuscate.cpp Hints: Don’t overthink this problem. Prompt the user to enter a collection o
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Answer:

In C++:

#include <iostream>

using namespace std;

int main(){

   string text,lengt;

   cout<<"Please enter obfuscated sentence: ";    cin>>text;

   cout<<"Please enter deobfuscation details: ";    cin>>lengt;

   string t1, t2;

   int kount = 0;

   for(int i = 0;i<lengt.length();i++){

   kount+=(int)(lengt[i]-'0');

   t1 = text.substr(0, kount);

   t2 = text.substr(kount, text.length()-1);

   text = t1 +" "+ t2;

   kount++;   }

   cout<<"Deobfuscated sentence: "<<text;

   return 0; }

Explanation:

This declares the text and the deobfuscation details as string

   string text,lengt;

This prompts for the sentence

   cout<<"Please enter obfuscated sentence: ";     cin>>text;

This prompts for the details

   cout<<"Please enter deobfuscation details: ";     cin>>lengt;

t1 and t2 are declared as string. They are used to split the texts into 2 parts

   string t1, t2;

This declares and initializes a count variable to 0  

   int kount = 0;

This iterates through the deobfuscation details

for(int i = 0;i<lengt.length();i++){

This gets each deobfuscation character

   kount+=(int)(lengt[i]-'0');

The next two instructions splits the text into 2

This gets from 0 to kount.

   t1 = text.substr(0, kount);

This gets from kount to the last index

   t2 = text.substr(kount, text.length()-1);

The new string or sentence is calculated here

   text = t1 +" "+ t2;

The kount variable is incremented by 1

   kount++;   } The loop ends here

This prints the new sentence

   cout<<"Deobfuscated sentence: "<<text;

<em>See attachment for program file</em>

Download cpp
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The reason for analyzing an algorithm is to discover its characteristics in order to evaluate its suitability for various applications are compared with other algorithms for the same application

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N= 67 I think I’m not sure
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