42in.^2 should be the answer that you are looking for. Hope this helps
1. Angles ADC and CDB are supplementary, thus
m∠ADC+m∠CDB=180°.
Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.
2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then
m∠CDB=m∠CBD=65°.
The sum of the measures of interior angles of triangle is 180°, therefore,
m∠CDB+m∠CBD+m∠BCD=180° and
m∠BCD=180°-65°-65°=50°.
3. Triangle ABC is isosceles, with base BC. Then
m∠ABC=m∠ACB.
From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So
m∠ACB=65°.
4. Angles BCD and DCA together form angle ACB. This gives you
m∠ACB=m∠ACD+m∠BCD,
m∠ACD=65°-50°=15°.
Answer: 15°.
A,C, E But if that doesnt work leave E out of it
Answer: 6cups of flour
Step-by-step explanation:
3cups of sugar to 2cups of flour
9cups of sugar to xcups of flour
Let sugar rep s
Flour rep f
So we have;
3s=2f
9s= xf
Cross multiply
3s×xf=2f×9s
Xf=2f×9s/3s
Xf=6f
Therefore, 9cups of sugar will be to 6cups of flour
